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aleksklad [387]
3 years ago
14

what are three activities in your everyday life that involve electromagnetic energy? and explain what type of electromagnetic en

ergy it is.
Physics
1 answer:
mihalych1998 [28]3 years ago
8 0

1). While I'm driving the car, I keep my eyes pointed out the front window,

so that LIGHT WAVES coming straight in through the front window get into

them. Using this process, I'm able to SEE what's in front of me, so that I don't

drive straight into it.


2). Also while I'm driving the car, I usually have the radio on, and I tune it

to a frequency where the RADIO WAVES that it responds to are being

modulated by people who are either talking or else playing classical music.


3). Before I leave the house on most days, I take a small container of

frozen Irish oatmeal out of the freezer, and I load it into the big box

above the stove, where MICROWAVE ENERGY thaws it, and warms

it to a nice eating temperature.


3A). When I arrive at my job, I usually do things that are also associated

in some way with MICROWAVE energy, since I work as a microwave

system design engineer. Most of the time it's just paperwork, but there

ARE times when I work with an actual radio that's either generating or

detecting real microwave energy, and either sending it up to, or receiving

it down from, a big dish antenna on a radio tower. Those are the days that

I like the best.

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A gas sample is confined within a chamber that has a movable piston. A small load is placed on the piston; and the system is all
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Explanation:

It is given that,

Total weight of the piston, W = F = 70 N

Area of the piston, a=5\times 10^{-4}\ m^2

Let P is the pressure exerted on the piston by the gas. The force per unit area is called the pressure exerted pressure of the gas. Mathematically, it is given by :

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We know that the atmospheric pressure is given by :

P_o=1.013\times 10^5\ Pa

So, the pressure is given by :

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p=2.41\times 10^5\ Pa

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Glycerin (C3H8O3) is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 154 g of glycerin to 316 mL o
garri49 [273]

Answer:

P_{sol}=50.4\ mm.Hg

Explanation:

According to given:

  • molecular mass of glycerin, M_g=3\times 12+8+3\times 16=92\ g.mol^{-1}
  • molecular mass of water, M_w=2+16=18\ g.mol^{-1}
  • ∵Density of water is 0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}
  • ∴mass of water in 316 mL, m_w=316\times 0.992=313.5 g
  • mass of glycerin, m_g=154\ g
  • pressure of mixture, P_x=55.32\ torr= 55.32\ mm.Hg
  • temperature of mixture, T_x=40^{\circ}C

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

<u>moles of water in the given quantity:</u>

n_w=\frac{m_w}{M_w}

n_w=\frac{313.5}{18}

n_w=17.42 moles

<u>moles of glycerin in the given quantity:</u>

n_g=\frac{m_g}{M_g}

n_g=\frac{154}{92}

n_g=1.674 moles

<u>Now the mole fraction of water:</u>

X_w=\frac{n_w}{n_w+n_g}

X_w=\frac{17.42}{17.42+1.674}

X_w=0.912

<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>

\therefore P_{sol}=X_w\times P_x

\therefore P_{sol}=0.912\times 55.32

P_{sol}=50.4\ mm.Hg

7 0
3 years ago
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