Ask question

Ask question

All categories

3 years ago

9

A Transformer has a primary coil with 650 turns if the output voltage is 500 volts and an input voltage of 200 volts how many te

rms will be needed by the secondary coil???
260
555
60
1,625

1 answer:

maxonik [38]3 years ago

6 0

Answer:

1625

Explanation:

Ns/Np = Vs/Vp

Ns / 650 = 500/200

Ns = 2.5 x 650

Ns = 1625

You might be interested in

The maximum current output of a 60 Ω circuit is 11 A. What is the rms voltage of the circuit?

qaws [65]

Ohm’s law states:

I*R = U

So we just fill in:

U = 11 A * 60 Ω = 660 V

8 0

3 years ago

<<br> 1<br> 2<br> 3<br> 4<br> 5<br> 6<br> 7<br> 8<br> 9<br> is a cell's main source of energy

andriy [413]

fat rat cat food dog money sleep houes

4 0

3 years ago

Max wants to see if mice that are fed food A grow faster than mice that are fed food B. He measures the mass of the mice each da

bezimeni [28]

I don't get what you're trying to say, I only see A. and B. so I will say the answer is possibly A.

6 0

3 years ago

Water evaporating from a pond does so as if it were diffusing across an air film 0.15 cm thick. The diffusion coefficient of wat

QveST [7]

Answer:

The water level will drop by about 1.24 cm in 1 day.

Explanation:

Here Mass flux of water vapour is given as

$j_{H_2O}=\frac{D}{l} \bigtriangleup c$

where

$j_{H_2O}$ is the mass flux of the water which is to be calculated.

D is diffusion coefficient which is given as $0.25 cm^2/s$

l is the thickness of the film which is 0.15 cm thick.
$\bigtriangleup c$ is given as

$\bigtriangleup c= \frac{P_{sat}-P_a}{RT}$

In this

$P_{sat}$ is the saturated water pressure, which is look up from the saturated water property at 20°C and 0.5 saturation given as 2.34 Pa

$P_a$ is the air pressure which is given as 0.5 times of $P_{sat}$

R is the universal gas constant as $8.314 kJ/kmol-K$

T is the temperature in Kelvin scale which is $20+273= 293K$

By substituting values in the equation

$\bigtriangleup c= \frac{P_{sat}-P_a}{RT} \\ \bigtriangleup c= \frac{P_{sat}-0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5 \times 2.34}{8.314 \times 293} \\\bigtriangleup c= 0.48 mol/m^3$

Converting $\bigtriangleup c$ into $cm^3/cm^3$

As 1 mole of water 18 $cm^3$ so

$\bigtriangleup c= 0.48 mol/m^3 \\ \bigtriangleup c= 0.48 \times 18 \times 10^{-6} cm^3/cm^3 \\ \bigtriangleup c= 8.64 \times 10^{-6} cm^3/cm^3$

Putting this in the equation of mass flux equation gives

$j_{H_2O}=\frac{D}{l} \bigtriangleup c \\ j_{H_2O}=\frac{0.25}{0.15} \times 8.64 \times 10^{-6} \\ j_{H_2O}=14.4 \times 10^{-6} cm/s$

For calculation of water level drop in a day, converting mass flux as

$j_{H_2O}=14.4 \times 10^{-6} \times 24 \times 3600 cm/day\\ j_{H_2O}=1.24 cm/day$

So the water level will drop by about 1.24 cm in 1 day.

7 0

3 years ago

5. Work is being done when a force

Artyom0805 [142]

Answer:

work is done when a force is applied. the force must not be zero and should make the object move through a certain distance.

4 0

2 years ago

Read 2 more answers