Explanation:
if we convert it into g/cm it'll be
2000 grams
A. fixed volume, changeable shape.
Answer:
Speed at bottom of the hill (v) = 11.74 m/s
Explanation:
Given:
Combined mass = 48.8 kg
Height h = 7.05 m
Find:
Speed at bottom of the hill (v)
Computation:
v² = 2gh
v = √2 x 9.8 x 7.05
v = √138.18
v = 11.74 m/s
Speed at bottom of the hill (v) = 11.74 m/s
Explanation:
It is given that,
Length of the string, l = 2 m
Mass of the string, 
Hanged mass in the string, 
1. The tension in the string is given by :


T = 1.96 N
2. Velocity of the transverse wave in the string is given by :

m = M/l


v = 28 m/s
Hence, this is the required solution.
Answer:
140Ns
Explanation:
From Newton's 2nd law of motion
F = ma
F = m∆v/t
==> Ft = m∆v
impulse = Ft = 400 × 0.35 = 140Ns