Question

A sample of gas originally at 25 C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 atm and the temperature is 15 C. The final volume of the gas is _____ L.A. 16.0 B. 1.00 C. 8.00 D. 2.00 E.4.00

Answer 1

Answer:

Final volumeof the gas = 2.84 L

Explanation:

The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.

The general gas equation is given as;

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

where;

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = Final pressure

V2 = Final volume

T2 = Final temperature

From the question,

P1 = 1.00 atm

P2 = 0.85atm

T1 = 25C + 273 = 298K (Converting to kelvin)

T2 = 15C + 273 = 288K (Converting to kelvin)

V1 = 2.5L

V2 = ?

from the equation, making V2 subject of formula we have;

$V2 = \frac{T2P1V1}{T1P2}$

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.