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Sveta_85 [38]
3 years ago
14

How to find the charge of an element

Chemistry
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

the atomic number is how you find the charge

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In an ionic bond:
inna [77]
Correct answer is 
<span>D. One atom accepts electrons from another.</span>
8 0
3 years ago
Read 2 more answers
Which missing item would complete this alpha decay reaction?<br><br> 257/100 Fm= ________+4/2He
maria [59]

Answer: ₉₈²⁵³Cf

253 is a superscript to the left of the symbol, Cf, which represents the mass number, and 98 is a subscript to the left of the same symbol, which represents the atomic number.

Explanation:

1) The alpha decay equation shows that the isotope Fm - 257, whose nucleus has 100 protons and 157 neutrons, emitted an alpha particle (a nucleus with 2 protons and 2 neutrons).

2) Therefore:

i) the mass number decreased in 4, from 257 to 257 - 4 = 253.

2) the atomic number decreased in 2, from 100 to 100 - 2 = 98.

3) Hence the formed atom has atomic number 98, which is californium, Cf, and the isotope is californium - 253.

4) The item that completes the given alpha decay reaction is:

₉₈²⁵³ Cf.

5) The complete alfpha decay reaction is:

₁₀₀²⁵⁷ Fm → ₉₈²⁵³Cf + ₂⁴He

You can verify the mass balance:

257 = 253 + 4, and

100 = 98 + 2

4 0
3 years ago
Read 2 more answers
Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma
kenny6666 [7]

Answer:

What do you need help with?!

Explanation:

5 0
2 years ago
What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
REY [17]

Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

5 0
3 years ago
Calculate the number of ATPs generated by the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol). Hydrolysis of
trapecia [35]

Answer:

Explanation:

412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)

130 ATP from the oxidation of palmitate

22 ATP from the oxidation of glycerol

Altogether 130 + 22 = 412 ATP will be produced.

Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.

When 51 carbons can produce 412 ATPs

Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.

This shows that ATP yield per carbon often oxidized will be 8.1 ATPs

Now we will see the ATP yield in the case of glucose.

Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs

When 6 carbons can yield 38 ATPs

Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.

So, ATP yield per carbon in case of glucose will be 6.33 ATPs

8 0
3 years ago
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