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daser333 [38]
3 years ago
11

Ma poate ajuta cineva?

Engineering
1 answer:
kari74 [83]3 years ago
5 0
Da, sigur. cu ce ai nevoie de ajutor?
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Kkhghghglgghklghghghlk
RideAnS [48]

Answer:

hLDskjdbKSABCLABJC

Explanation:

BECAUSE

3 0
4 years ago
Read 2 more answers
The flowrate through a rectangular channel is 20 cfs. The upstream width of the channel is 10 ft, and the depth of the water in
Liula [17]

To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,

Q = 20cfs\\w= 10ft\\D= 1ft

Then the velocity would be:

V = \frac{Q}{wD}V = \frac{20}{10*1}V = 2ft/s

The number of Froude is given as,

Fr = \frac{V}{gD}^{1/2}

Where,

V = Velocity

g = Gravity

D = Diameter

Replacing we have that

Fr = \frac{2}{32.2}^{1/2}\\Fr = 0.352\\Fr

There will be no Jump, correct answer is B.

5 0
3 years ago
13–27. The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-k
Feliz [49]

Answer:

See explanation for step by step procedure to get answer.

Explanation:

Given that:

The conveyor belt is moving downward at 4 m>s. If the coefficient of static friction between the conveyor and the 15-kg package B is ms = 0.8, determine the shortest time the belt can stop so that the package does not slide on the belt.

See the attachments for complete steps to get answer.

4 0
4 years ago
Pls help me answer my module
Otrada [13]

Answer:

Hand tools based on job requirement and its importance and the classification of hand tools according to its function and its importance are discussed below in details.

Explanation:

Hand tools based on work requirement is essential because Every tool is specifically invented for a particular purpose, so picking the accurate tool will also reduce the amount of energy needed to get work done right without causing injury or harm to either the tools or the exterior being worked on.

classifying of hand tools: wrenches, screwdrivers, cutters, striking tools, hammer tool or struck, pliers, vise, clamps, snips, saws, drills, and knives.

4 0
4 years ago
Calculate the LER for the rectangular wing from the previous question if the weight of the glider is 0.0500 Newton’s.
lapo4ka [179]

Answer:

0.2

Explanation:

Since the span and chord of the rectangular wing is missing, due to it being from the other question, permit me to improvise, or assume them. While you go ahead and substitute the ones from your question to it, as it's both basically the same method.

Let the span of the rectangular wing be 0.225 m

Let the chord of the rectangular wing be 0.045 m.

Then, the area of any rectangular chord is

A = chord * span

A = 0.045 * 0.225

A = 0.010 m²

And using the weight of the glider given to us from the question, we can find the LER for the wing.

LER = Area / weight.

LER = 0.010 / 0.05

LER = 0.2.

Therefore, using the values of the rectangular wing I adopted, and the weight of the glider given, we can see that the LER of the glider is 0.2

Please mark brainliest...

3 0
3 years ago
Read 2 more answers
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