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Mamont248 [21]
3 years ago
14

In which direction does the electric field point a position directly south of a positive charge?

Chemistry
1 answer:
Stella [2.4K]3 years ago
7 0

Answer: Outward

Explanation: :The direction of electric field is radially outward for a positive charge and radially inward for a negative charge. Thus, for the electric field points toward south at a position directly south of a positive charge.

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100 n to the right

Explanation:

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What do El Niño and La Niña have in common? Check all that apply.
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How many moles of each reactant are needed to produce 3.60 x 10^2g ch3oh
zysi [14]
Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,

                                   CO  +  2 H₂    →    CH₃OH

Calculating Moles of CO:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  1 Mole of CO
So,
             3.60 × 10² g of CH₃OH is produced by  =  X Moles of CO

Solving for X,
                       X  =  (3.60 × 10² g × 1 Mole) ÷ 32 g

                       X  =  11.25 Moles of CO

Calculating Moles of H₂:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  2 Mole of H₂
So,
             3.60 × 10² g of CH₃OH is produced by  =  X Moles of H₂

Solving for X,
                       X  =  (3.60 × 10² g × 2 Mole) ÷ 32 g

                       X  =  22.5 Moles of H₂

Result:
            3.60 × 10² g of CH₃OH
is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.
3 0
3 years ago
What is the energy of a wave with wavelength of 4.2 x 10-7 m. (Hint: Calculate for frequency first.)
erik [133]

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

Energy (E) =.?

Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

5 0
3 years ago
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