Solve B in a complete combustion pleaseee
1 answer:
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<u>Answer:</u> The equilibrium constant of the reaction is 0.0526 and standard Gibbs free energy of the reaction is -7.296 kJ/mol
<u>Explanation:</u>
For the given chemical equation:
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
The equation used to calculate standard Gibbs free energy of the reaction follows:
where,
= Standard Gibbs free energy
R = Gas constant = 8.314 J/K mol
T = Temperature =
= Equilibrium constant of the reaction = 0.0526
Putting values in above equation, we get:
Hence, the equilibrium constant of the reaction is 0.0526 and standard Gibbs free energy of the reaction is -7.296 kJ/mol