Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
Answer:

Explanation:
A number can be written in the form of :

Where
m is the real number
n is any integer
In this case, the average distance from the Sun to the Earth is given,
d = 150000000000 meters
There are 10 zeroes in this number. We need to write this number in scientific notation. It is given by :

So, the average distance from the Sun to the Earth is
. Hence, this is the required solution.
Is proportional to the CHANGE.
hope this helps
Hmm doesnt soujd familiar