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erastovalidia [21]
3 years ago
8

In deep space, sphere A of mass MA is located at the origin of an x axis and sphere B of mass MB is located on the axis at a poi

nt x1. Sphere B is released from rest while sphere A is held at the origin. (a) What is the gravitational potential energy of the two-sphere system just as B is released
Physics
1 answer:
Nookie1986 [14]3 years ago
6 0

Answer:

The gravitational potential energy of the two-sphere system just as B is released is

U = -[(G)(MA)(MB)/x₁]

where G = Gravitational constant

G = (6.7 × 10⁻¹¹) Nm²/kg²

Explanation:

The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as

U = -(GMm/d)

For our question,

Mass of object 1 = MA

Mass of object 2 = MB

Distance between them = x₁

U = -[(G)(MA)(MB)/x₁]

where G = Gravitational constant

G = (6.7 × 10⁻¹¹) Nm²/kg²

Hope this Helps!!!

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How to create or build a homemade golf club. is this possible? If so, what suggestion did you find? Do you have an original idea
goldenfox [79]

Answer:

All you need is golfing equipment make a small hole in the ground and have like something to cover the sun off of you and boom you got a golfing spot and a golf club no skills needed. Oh and you need a small flag for your gold hole but then your good and you can have fun

Explanation:

8 0
2 years ago
How are energy and mass connected during the formation of an atom? Energy is absorbed, so the mass is increased. Energy is relea
zloy xaker [14]

Answer:

Energy is absorbed, so the mass is reduced.

Explanation:

The relationship between the mass and the energy is given by Einstein formula as :

E=mc^2

m is the mass of an atom

c is the speed of light

When an atom is formed, the energy gets absorbed. As a result mass will decrease as per Einstein's equation. So, the correct option is (c) "Energy is absorbed, so the mass is reduced".

4 0
3 years ago
Read 2 more answers
In the equation F = Kq1 q2/r2 solve for q2. Solve for r.
Tpy6a [65]

Answer:

r = √(k q₁ q₂ / F)

Explanation:

F = k q₁ q₂ / r²

Multiply both sides by r²:

F r² = k q₁ q₂

Divide both sides by F:

r² = k q₁ q₂ / F

Take the square root of both sides:

r = √(k q₁ q₂ / F)

3 0
3 years ago
21. A toy car starts from rest and begins to
Bond [772]

Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

Acceleration of the car, a = 11 m/s²

We need to find the final velocity of the toy after 6 seconds.

Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

v = u +at

v = 0 + 11 m/s² × 6 s

v = 66 m/s

So, the final velocity of the car is 66 m/s.

8 0
3 years ago
A body weighs 100newtons when submerged in water. calculate the upthrust action on the body​
Andrews [41]

Answer:

Upthrust = 20 N

Explanation:

The question says that "A body weighs 100N in air and 80N when submerged in water. Calculate the upthrust acting on the body ?"

Upthrust is defined as the force when a body is submerged in liquid, then liquid applies a force on it.

ATQ,

Weight of body in air is 100 N

Weight of body in water is 80 N

Upthrust is equal to the weight of body in air minus weight of body in water.

Upthrust = 100 N - 80 N

Upthrust = 20 N

So, 20 N of upthrust is acting on the body.

7 0
3 years ago
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