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Alexxx [7]
3 years ago
6

You suspect that an uninterruptible power supply (UPS) is malfunctioning. You need to test the output from the UPS using a multi

meter. Which multimeter setting should you use?A) AC VoltageB) DC VoltageC) Ohms
D) Continuity
Physics
1 answer:
zmey [24]3 years ago
7 0

Answer:

Option A

Explanation:

An Uninterruptible Power Supply abbreviated as UPS is used in case of the failure of the power mains or the input power in order to ensure uninterrupted power supply.

The Ac voltage is first converted to DC and then again inverted to the AC and is fed to the system.

Thus if the UPS malfunctions then in order to check the output using multimeter we use AC voltage setting because the UPS purely supplies AC power, even if the power is  supplied from its internal battery then also it inverts the DC into AC and then supply.

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Why are nuclear power plants controversial
Sliva [168]
Because a nuclear meltdown can be caused if systems fail. 
6 0
3 years ago
The temperature and time t given in hours from 0 to 24 after midnight in downtown mathville is given by t=10-5 sin(pi/12 t) degr
Dvinal [7]

Answer:

T_A_v_g=9.918192559$^{\circ}C

Explanation:

The problem tell us that the temperature as function of time in downtown mathville is given by:

T(t)=10-5*sin(\frac{\pi}{12t})

The average temperature over a given interval can be calculated as:

T_a_v_g=\frac{T_o+T_f}{2}

Where:

T_o=Initial\hspace{3}temperature\\T_f=Final\hspace{3}temperature

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:

Therefore:

T_o=T(12)=10-5*sin(\frac{\pi}{12*12}) =9.890925575$^{\circ}C

T_f=T(24)=10-5*sin(\frac{\pi}{12*24}) =9.945459543$^{\circ}C

Hence, the average temperature between noon and midnight is:

T_A_v_g=\frac{9.890925575+9.945459543}{2}=9.918192559$^{\circ}C

3 0
3 years ago
Copernicus patterned his concept of the solar system after that of
Rasek [7]

Answer:

Aristarchus

Explanation:

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3 0
3 years ago
QUESTION 36
mel-nik [20]

Answer:

Explanation:

m = ρV = 1.03( 1000 kg/m³)(π(2² m²)(3.0 m)) = 12360π kg

m ≈ 38,830 kg

5 0
3 years ago
A football player with a mass of 85 kg wears a uniform and helmet that have a mass of 4.5 kg. The football player moves at 2.1 m
DochEvi [55]
The answer would be 187.95 kg.m/s.

To get the momentum, all you have to do is multiply the mass of the moving object by the velocity. 

p = mv

Where:
P = momentum
m = mass
v = velocity

Not the question is asking what is the total momentum of the football player and uniform. So we need to first get the combined mass of the football player and the uniform. 

Mass of football player = 85.0 kg
Mass of the uniform     = <u>  4.5 kg</u>
TOTAL MASS                  89.5 kg

So now we have the mass. So let us get the momentum of the combined masses. 

p = mv
   = (89.5kg)(2.1m/s)
   = 187.95 kg.m/s

5 0
3 years ago
Read 2 more answers
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