Answer:C
Explanation:
Mass energy of hydrogen fusing into helium
Heat is added to the mass as follows:
Q_-14-0 = mC_iΔT = 39*2.06*(0--14) = 39*2.06*14 = 1124.76 J
Q_0 = mC_f = 39*334 = 13026 J
Q_0-100 = mC_wΔT = 39*4.18*100 = 16302 J
Q_100 = mC_v = 39*2230 = 86970 J
Q_100-108 = mC_sΔT = 39*2.03*(108-100) = 39*2.03*8 = 633.36J
Q = Summation of all the heats added = 1124.76+13026+16302+86970+633.36 = 118056.12 J ≈ 118.06 kJ
It means that 19.3g of gold is packed into 1cm^3.
Answer:
a small dense nucleus with positive charge and the nucleus is surrounding by orbiting electrons.
Explanation:
An experiment in which alpha particles were used to bombard thin sheets of gold foil led to the conclusion that an atom is composed mostly of a small dense nucleus with positive charge and the nucleus is surrounding by orbiting electrons.
