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3 years ago

6

If you were to mix 3 liters of 20 degrees celsius water with 4 liters of 30 degrees water at 7 liters of water what temperature

1 answer:

Debora [2.8K]3 years ago

3 0

Lets say final temperature is @ celsius
3c(@-20)= 4c([email protected])
[email protected]=180
@=180/7

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Solving for $L$ we get

$L = \dfrac{T^2g}{4\pi^2}$

putting in $T =5.0s$ and $g =9.8m/s^2$ we get:

$L = \dfrac{(5.0s)^2*9.8m/s^2}{4\pi^2}$

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putting in $F =30N$ , $m =5.0kg$ , and $g =9.8m/s^2$ we get

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