The mass of the first block will be three times the mass of the second block.
According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;


F is the acting force
m is the mass
a is the acceleration of the body
Given the following parameters
Constant force F = 1N
For the first block with the acceleration of "a"
1 = m₁a
a = m₁/1
m₁ = a .................1
For the second block, acceleration is thrice that of the first. This means;
F = m(3a)
1 = 3ma
..........................2
Divide both equations

From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.
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For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in kJ. We use the conversion: 1000 cal = 4.184 kJ The solution is as follows:
<span>6.95×10</span>⁵<span> cal * 4.184 kJ/1000 cal = 2,907.88 kJ</span>
Answer: option d. gives the percentage of water molecules in the air.
Explanation:
Answer:
a) 0.040625 m
b) 5.02272 J
Explanation:
k = Spring constant
x = Stretched length
F = Force
a)


Extension of the spring would be 0.040625 m
b) Work done in a spring

The work done by the shopper to stretch this spring a total distance of 8.00 cm is 5.02272 J