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Goshia [24]
3 years ago
7

Give two examples of motion related to civil engineering.​

Physics
1 answer:
krok68 [10]3 years ago
7 0

rotational motion of a concrete mixer

linear motion of a tractor

is this what you mean

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A force of 1 N is the only horizontal force exerted on a block, and the horizontal acceleration of the block is
SVEN [57.7K]

The mass of the first block will be three times the mass of the second block.

According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;

F\ \alpha \ a

F = ma

F is the acting force

m is the mass

a is the acceleration of the body

Given the following parameters

Constant force F =  1N

For the first block with the acceleration of "a"

1 = m₁a

a = m₁/1

m₁ = a .................1

For the second block, acceleration is thrice that of the first. This means;

F = m(3a)

1 = 3ma

m_2=\frac{1}{3a} ..........................2

Divide both equations

\frac{m_1}{m_2} =\frac{a}{(\frac{1}{3a} )}\\\frac{m_1}{m_2} = 3\\m_1 = 3m_2

From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.

Learn more here: brainly.com/question/19030143

4 0
3 years ago
Convert 6.95×105 cal to joules. recall that 1 cal=duncan takes a break from studying and goes to the gym to swim laps. if swimmi
quester [9]
For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in kJ. We use the conversion: 1000 cal = 4.184 kJ The solution is as follows:

<span>6.95×10</span>⁵<span> cal * 4.184 kJ/1000 cal = 2,907.88 kJ</span>
3 0
4 years ago
Characteristics
MAXImum [283]
The answer is B. Comet
6 0
4 years ago
Relative humidity _______.
horsena [70]

Answer: option d. gives the percentage of water molecules in the air.

Explanation:

4 0
3 years ago
A shopper weighs 4.00 kg of apples on a supermarket scale whose spring obeys Hooke's law and notes that the spring stretches a d
Irina-Kira [14]

Answer:

a) 0.040625 m

b) 5.02272 J

Explanation:

k = Spring constant

x = Stretched length

F = Force

a)

F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{4\times 9.81}{0.025}\\\Rightarrow k=1569.6\ N/m

F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{6.5\times 9.81}{1569.6}\\\Rightarrow x=0.040625\ m

Extension of the spring would be 0.040625 m

b) Work done in a spring

W=\frac{1}{2}kx^2\\\Rightarrow W=\frac{1}{2}\times 1569.6\times 0.08^2\\\Rightarrow W=5.02272\ J

The work done by the shopper to stretch this spring a total distance of 8.00 cm is 5.02272 J

4 0
3 years ago
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