Question

A circular loop of radius 0.10 m is rotating in a uniform magnetic field of 0.20 T. Find the magnetic flux through the loop when the plane of the loop and the magnetic field vector are at an angle of 30 degree with each other.

Answer 1

Answer:

Magnetic flux will be equal to $5.43\times 10^{-3}weber$  

Explanation:

It is given radius of circular loop r = 0.10 m

Area of circular loop $A=\pi r^2$

$A=3.14\times 0.10^2=0.0314m^2$

Magnetic field B = 0.20 T

Angle between plane of loop and magnetic field $\Theta =30^{\circ}$

Magnetic flux will be equal to $\Phi =BAcos\Theta$

$\Phi =0.2\times 0.0314\times cos30^{\circ}=5.43\times 10^{-3}weber$

So magnetic flux will be equal to $5.43\times 10^{-3}weber$