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3 years ago

what would be the value of 'G' on the surface of earth if it's mass was twice & its radius half of what it is how?

Chemistry

2 answers:

Katen [24]3 years ago

8 0

Answer:

What would be the value of g on the surface of the earth if its mass was twice and its radius half of what it is now ? g2=8g1 Thus , the value of g on the surface of the earth would be eight times the present value.

Explanation:

Hope this helps! :)

son4ous [18]3 years ago

8 0

Explanation:

What could be the value of g on the surface of Earth if its mass were twice as large, and the radius also twice what it is now?

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Andreas Xi

Updated 1 year ago

G would be half of what it is now, since it is proportional to mass and inversely proportional to distance squared. Such a planet would be only a little more dense than water, quite similar to Neptune, but smaller.

See below for the answer to the (completely different) original question:

What would be the value of g on the surface of the earth if its mass was twice as large and its radius half of what it is now?

G would be eight times larger, since it is proportional to mass and inversely proportional to distance squared. [Thanks to Niels for pointing out an earlier mistake]

The Earth would need to be 16 times as dense, though, which is quite impossible. The density of rock is around 3 g/cm^3, of iron around 8 and the Earth overall (consisting mostly of those two materials, including compression) around 6. The densest known material is around 22 g/cm^3 (Osmium), which is only roughly 4 times as much. Even when you consider increased compression, no planet could possibly satisfy your conditions, even if it were made of pure Osmium.

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Food and medical procedures can expose people to radiation. Therefore, the effects of radiation from a nuclear power plant are n

iogann1982 [59]

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3 years ago

Read 2 more answers

White vinegar is a 5.0% by mass solution of acetic acid in water. If the density of white

Alex_Xolod [135]

The pH = 2.41

<h3>Further explanation</h3>

Given

5.0% by mass solution of acetic acid

the density of white vinegar is 1.007 g/cm3

Required

Solution

Molarity of solution :

$\tt M=\dfrac{\%mass\times \rho\times 10}{MW~acetic~acid}\\\\M=\dfrac{5\times 1.007\times 10}{60}\\\\M=0.839$

Ka for acetic acid = 1.8 x 10⁻⁵

[H⁺] for weak acid :

$\tt [H^+]=\sqrt{Ka.M}$

Input the value :

$\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.839}\\\\(H^+]=0.00388=3.88\times 10^{-3}\\\\pH=3-log~3.88=2.41$

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3 years ago

Which of the following is a radioactive element?Sodium, Fluorine,Oxygen <br> francium

Maksim231197 [3]

Answer:

Fluorine

Explanation:

These particles stick in the atoms and make them radioactive.

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3 years ago

Choose the solvent below that would show the greatest freezing point lowering when used to make a 0.20 m nonelectrolyte solution

tatiyna

Answer : Carbon tetrachloride, $k_f=29.9^oC/m$ will show the greatest freezing point lowering.

Explanation :

For non-electrolyte solution, the formula used for lowering in freezing point is,

$\Delta T_f=k_f\times m$

where,

$\Delta T_f$ = lowering in freezing point

$k_f$ = molal depression constant

m = molality

As per question, the molality is same for all the non-electrolyte solution. So, the lowering in freezing point is depend on the $k_f$ only.

That means the higher the value of $k_f$ , the higher will be the freezing point lowering.

From the given non-electrolyte solutions, the value of $k_f$ of carbon tetrachloride is higher than the other solutions.

Therefore, Carbon tetrachloride, $k_f=29.9^oC/m$ will show the greatest freezing point lowering.

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3 years ago

How do I find the slope of this graph? Is it even possible?

nasty-shy [4]

Answer:

Not exactly But you can take the slope of the curved portion and the slope of the flatline.

It wont do you much good since your working for absorbance but if you ever see something like a temperature change you can use the slope(s) to find freezing points/melting

Explanation:

If you need to submit a slope you could use a best fit which is just point to point or you could break it up like i mentioned

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3 years ago

what would be the value of 'G' on the surface of earth if it's mass was twice & its radius half of what it is how?​

what would be the value of 'G' on the surface of earth if it's mass was twice & its radius half of what it is how?