Answer:
The fulcrum of the metre stick is at the 40 cm mark
100 g * 10 cm = 1000 g-cm clockwise torque
x * 30 cm = 1000 gm-cm = counterclockwise torque for balance
X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm at 10 cm to balance
Heya!!
For calculate aceleration, let's applicate second law of Newton:

⇒ Being:
→ F = Force = 12 N
→ m = Mass = 3 kg
→ a = aceleration = ?
Lets replace according formula and leave the "a" alone:



Result:
The aceleration of the object is of <u>4 m/s²</u>
The electrostatic force between two charges is given by

where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges
In our problem,



Therefore the electrostatic force is