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dexar [7]
3 years ago
11

The common value for the speed of light in a vacuum is:

Physics
1 answer:
OLEGan [10]3 years ago
5 0

The common value for “Speed of light in vacuum” is \bold{3 \times 10^{8}}  metre per second.

Answer: Option b

<u>Solution: </u>

Speed of light can be defined as the speed with which light waves propagate in different medium. In vacuum, speed of light is 186,282 miles per second or 299,792 km/s which is rounded off as 3 \times 10^{8} \mathrm{m} / \mathrm{s}.

“Speed of light in vacuum” is a universal constant and usually represented by ‘c’. Light waves travels at a speed of 3 \times 10^{8}  metre per second in vacuum.

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Answer:

health factors that could harm you or your offspring

3 0
2 years ago
8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer
Sonbull [250]

Answer:

the distance that the object is raised above its initial position is 5.625 m.​

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \  by \ the \ effort}{disatnce \ moved \  by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m

Therefore, the distance that the object is raised above its initial position is 5.625 m.​

3 0
2 years ago
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
Step2247 [10]

The final volume of the gas is 144.25 L

Explanation:

For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by

W=p\Delta V = p(V_f - V_i)

where

p is the pressure of the gas

V_i is the initial volume

V_f is the final volume

For the gas in the cylinder in this problem,

p = 2.00 atm

V_i = 0.250 L

And we also know the work done,

W = 288 J

So we can solve the equation for V_f, the final volume:

V_f = V_i + \frac{W}{p}=0.250 + \frac{288}{2.00}=144.25 L

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

7 0
2 years ago
An car has an acceleration of 8.0 m/s/s. How much time is needed to reach a velocity of 30 m/s from
polet [3.4K]

Answer:

3.75s

Explanation:

a = 8.0 m/s V = 30 m/s U = 0 m/s t = ?

t = V - U/a

t = 30 - 0/8

t = 30/8 = 15/4

t = 3.75s

5 0
3 years ago
A ball of mass m is dropped from rest from a height h and collides elastically with the floor, rebounding to its original height
Jet001 [13]

Answer:

Explanation:

Given

mass m collides elastically with floor and jump to its original height I .e.velocity of rebound is same as the initial velocity

Impulse imparted by steel ball to the ground is given by the change in momentum of steel ball

J=\Delta P

and impulse is product of average force and time

so we need time to calculate the average force. So, option e is correct

3 0
2 years ago
Read 2 more answers
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