Question

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the equation H 2 S O 4 + 2 N a O H ⟶ 2 H 2 O + N a 2 S O 4 If you require 28.07 mL of 0.697 M NaOH solution to titrate 220.1 mL of H 2 SO 4 solution, what is the concentration of the H 2 SO 4 solution? Type answer:

Answer 1

Answer:

$M_{acid}=0.0444M$

Explanation:

Hello,

In this case, for the given reaction:

$H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4$

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

$2*n_{acid}=n_{base}$

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

$2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M$

Best regards.