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lara31 [8.8K]
3 years ago
10

Draw an atomic model from1 to 20 elements with their symbol valency and electronic configuration​

Chemistry
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

MARK AS THE BRAINLIEST ANSWER

Explanation:

BRAINLIEST

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How many grams of silver chromate, Ag2CrO4, are produced from 57.7
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48.3 g AgNO3 / 169.9 g/mol = 0.284 moles AgNO3
0.284 mol AgNO3 X (1 mol Ag2CrO4/2 mol AgNO3) = 0.142 mol Ag2CrO4
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Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decoxide and water, as
erica [24]

<u>Answer:</u> The amount of P_4O_{10} formed is 469.8 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ......(1)

Given mass of phosphine = 225 g

Molar mass of phosphine = 34 g/mol

Putting values in equation 1, we get:

\text{Moles of phosphine}=\frac{225g}{34g/mol}=6.62mol

The given chemical reaction follows:

4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)

Assuming that oxygen gas is present in excess, it is considered as an excess reagent.

Phosphine is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of phosphine produces 1 mole of P_4O_{10}

So, 6.62 moles of phosphine will produce = \frac{1}{4}\times 6.62=1.655mol of P_4O_{10}

Now, calculating the mass of P_4O_{10} by using equation 1:

Molar mass of P_4O_{10} = 283.9 g/mol

Moles of P_4O_{10} = 1.655 moles

Putting values in equation 1, we get:

1.655mol=\frac{\text{Mass of }P_4O_{10}}{283.9g/mol}\\\\\text{Mass of }P_4O_{10}=(1.655mol\times 283.9g/mol)=469.8g

Hence, the amount of P_4O_{10} formed is 469.8 grams.

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300cm cubed ( have a great night! )
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Can someone please help me please dont scroll
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Quantitative is anything that is relating to a number value. Think “quantity”

Example:

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