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Salsk061 [2.6K]
3 years ago
5

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much

electric power does the power plant output?
Physics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

 P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

\eta = \dfrac{P_0}{P}

where P is the power produced in the power plant

          P₀ is the power output of the power plant

\eta = \dfrac{P_0}{P}

0.32 = \dfrac{P_0}{0.18}

 P₀ = 0.18 x 0.32

 P₀ =  0.0576 MW

 P₀ = 5.76 x 10⁻² MW

Power plant output is equal to  P₀ = 5.76 x 10⁻² MW

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Explanation:

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The image formed is enlarged and it is erect. So the magnification will be positive (+) and greater than 1.

Refer above image. 1

(ii)

O is the object and I is the image.

The image formed is diminished and erect. So the magnification will be positive (+) and less than1.

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(iii)

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The measure of a spring’s resistance to being compressed or stretched is the
larisa86 [58]

<u>Answer;</u>

<em>Spring constant </em>

<u>Explanation;</u>

The measure of a spring’s resistance to being compressed or stretched is the <u>spring constant</u>.

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were the final velocity is zero, v = 0 and the initial velocity v₀= 16m/s:
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The total breaking distance is the sum of the two parts:
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