Question

A nuclear fission power plant has an actual efficiency of 32%. If 0.18 MW of power are produced by the nuclear fission, how much electric power does the power plant output?

Answer 1

Answer:

 P₀ = 5.76 x 10⁻² MW

Explanation:

given,

efficiency of the power plant = 32%

Power produced by the nuclear fission = 0.18 MW

the power plant output = ?

using formula of efficiency

$\eta = \dfrac{P_0}{P}$

where P is the power produced in the power plant

          P₀ is the power output of the power plant

$\eta = \dfrac{P_0}{P}$

$0.32 = \dfrac{P_0}{0.18}$

 P₀ = 0.18 x 0.32

 P₀ =  0.0576 MW

 P₀ = 5.76 x 10⁻² MW

Power plant output is equal to  P₀ = 5.76 x 10⁻² MW