What to you do if you have a flat tirer

Degreasers can be broken down into two main categories

Alex17521 [72]

Degreasers can be categorized to be either water-based or solvent-based.

5 0

3 years ago

Write a program that randomly chooses between three different colors for displaying text on the screen. Use a loop to display tw

11Alexandr11 [23.1K]

Answer:

INCLUDE Irvine32.inc

.data

msgIntro byte "This is Your Name's fourth assembly extra credit program. Will randomly",0dh,0ah

byte "choose between three different colors for displaying twenty lines of text,",0dh,0ah

byte "each with a randomly chosen color. The color probabilities are as follows:",0dh,0ah

byte "White=30%,Blue=10%,Green=60%.",0dh,0ah,0

msgOutput byte "Text printed with one of 3 randomly chosen colors",0

.code

main PROC

;

//Intro Message

mov edx,OFFSET msgIntro ;intro message into edx

call WriteString ;display msgIntro

call Crlf ;endl

call WaitMsg ;pause message

call Clrscr ;clear screen

call Randomize ;seed the random number generator

mov edx, OFFSET msgOutput;line of text

mov ecx, 20 ;counter (lines of text)

L1:;//(Loop - Display Text 20 Times)

call setRanColor ;calls random color procedure

call SetTextColor ;calls the SetTextColor from library

call WriteString ;display line of text

call Crlf ;endl

loop L1

exit

main ENDP

;--

setRanColor PROC

;

; Selects a color with the following probabilities:

; White = 30%, Blue = 10%, Green = 60%.

; Receives: nothing

; Returns: EAX = color chosen

;--

mov eax, 10 ;range of random numbers (0-9)

call RandomRange ;EAX = Random Number

.IF eax >= 4 ;if number is 4-9 (60%)

mov eax, green ;set text green

.ELSEIF eax == 3 ;if number is 3 (10%)

mov eax, blue ;set text blue

.ELSE ;number is 0-2 (30%)

mov eax, white ;set text white

.ENDIF ;end statement

ret

setRanColor ENDP

6 0

4 years ago

A unidirectional E-Glass fiber-epoxy composite material contains 61% by volume E-Glass fibers stressed under isostrain condition

zalisa [80]

Answer:

The total load carried by the fiber will be "98%".

Explanation:

The given values are:

$V_{f}=0.61$

$V_{m}=1-V_{f}$

$=1-0.61$

$=0.39$

$E_{f}=10 \ Mpa$

$\sigma_{f}=0.35 \ Mpa$

$E_{m}=0.45 \ Mpa$ , $\sigma_{m}=9\times 10^{-3} \ Mpa$

As we know,

⇒ $E_{e}=fE_{f}+mE_{m}$

On putting the estimated values, we get

⇒ $=0.61\times 10+0.39\times 0.95$

⇒ $=6.27 \ Mpa$

Now,

⇒ $\sigma_{c}=f\sigma_{f}+m\sigma_{m}$

On putting the estimated values, we get

⇒ $=0.61\times 0.35+0.39\times 0.009$

⇒ $=0.217 \ Mpa$

Therefore,

The load carried by fiber,

$=\frac{f\sigma_{f}}{\sigma_{c}}$

$=\frac{0.35\times 0.61}{0.217}$

$=0.98$ i.e., 98%

4 0

4 years ago

Aerospace engineers who work for certain government agencies are often required to have security clearance. Explain two reasons

yuradex [85]

Answer:

Two reasons that justify the requirement for security clearance for aerospace engineers working for government agencies are;

1) Such engineers have access to data regarding the blueprint, components, method of construction, functionality status, new systems design, future systems design, inventory of systems and aeronautical systems database which are sensitive information that are of high importance to the federal government

2) Such engineers take part in the testing of aeronautic equipment, and will require security clearance to be able to input data results into the data base of the aeronautic equipment

Explanation:

3 0

3 years ago

A 60 mm radium drum is rigidly attached to a 100 mm radius drum as shown. One of the drum rolls without sliding on the surface s

Sliva [168]

The acceleration at points A, B and C are respectively; 960 mm²/s, 1600 mm²/s and 600 mm²/s

<h3>What is the acceleration?</h3>

The drum rolls without sliding and as such its' instantaneous center will lie at B. Thus;

V_d = V_c = 160 mm/s

Also, a_d = a_c = 600 mm²/s

Now, formula for velocity at A is;

V_a = r_ab * ω

where ω = 160/(100 - 60)

ω = 4 rad/s

V_a = 60 * 4

V_a = 240 mm/s

Acceleration at A = V_a²/r_ab

Acceleration at A = 240²/60 = 960 mm²/s

Now, V_b = 100 * 4 = 400 mm/s

Acceleration at B = 400²/100 = 1600 mm²/s

Read more about Acceleration at; brainly.com/question/14344386

6 0

2 years ago