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lesya692 [45]
3 years ago
6

A car is travelling at 50km/h. After 12 seconds, it is now travelling at 60km/h. What is the car’s acceleration

Physics
1 answer:
astra-53 [7]3 years ago
7 0

Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (starting speed)

Change in speed = (60 km/hr) - (50 km/hr) = 10 km/hr

Time for the change = 12 sec

Acceleration = (10 km/hr) / (12 sec)

Acceleration = 0.8333 km/hr-sec

Convert to a unit that we can understand:

Acceleration = (0.8333 km/hr-sec)x(1000 m/km)x(hr/3600sec)

Acceleration = (833.3 / 3600) (m-hr / hr-sec²)

Acceleration = (833.3 / 3600) (m/s²)

<em>Acceleration = 0.231 m/s² </em> or  0.833 km/hr-sec²


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What is the energy of a photon whose frequency is 6.0 x 10^20?
omeli [17]

Answer:

3.75 MeV

Explanation:

The energy of the photon can be given in terms of frequency as:

E = h * f

Where h = Planck's constant

The frequency of the photon is 6 * 10^20 Hz.

The energy (in Joules) is:

E = 6.63 x10^(-34) * 6 * 10^(20)

E = 39.78 * 10^(-14) J = 3.978 * 10^(-13) J

We are given that:

1 eV = 1.06 * 10^(-19) Joules

This means that 1 Joule will be:

1 J = 1 / (1.06 * 10^(-19)

1 J = 9.434 * 10^(18) eV

=> 3.978 * 10^(-13) J = 3.978 * 10^(-13) * 9.434 * 10^(18) = 3.75 * 10^(6) eV

This is the same as 3.75 MeV.

The correct answer is not in the options, but the closest to it is option C.

6 0
3 years ago
A bird flies 10 miles south, turns and flies 15 miles east. What distance did it fly.
vfiekz [6]

Answer:

wouldn't it be 25 miles?? yeah

Explanation:

4 0
3 years ago
A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object
Darya [45]

Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

Force acting along +x direction, F_x=8\ N

Force acting along +y direction, F_y=6\ N

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}

Here \theta=90^{\circ}

R=\sqrt{F_x^2+F_y^2}

R=\sqrt{8^2+6^2}

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0
3 years ago
Which single force acts on a object in a free fall
11Alexandr11 [23.1K]

Answer:

weight!!!! Free fall is the motion of a body where its weight is the only force acting on an object.

4 0
3 years ago
A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

8 0
3 years ago
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