Answer:
<em>A = 6.9 cm</em>
Explanation:
<u>Simple Harmonic Motion</u>
A mass-spring system is a common example of a simple harmonic motion device since it keeps oscillating when the spring is stretched back and forth.
If a mass m is attached to a spring of constant k and they are set to oscillate, the angular frequency of the motion is
The equation for the motion of the object is written as a sinusoid:
Where A is the amplitude.
The instantaneous speed is computed as the derivative of the distance
And the maximum speed is
Solving for the amplitude
Computing w
Calculating A
Precipitation from the sky to the earth can come in several forms. Four types are:
1) Rain
2) Snow
3) Sleet (think of a more liquidity slushy snow)
4) Hail (pretty much solid chunks of ice)
1)Food is crushed and ground in the mouth by teeth
2)Chewed food is pushed into the pharynx
3)Food enters the esophagus
4)Food passes through a valve and into the stomach
5)Food is broken down by pancreatic enzymes and absorbed by the small intestine
6)Undigested material is pushed into the large intestine
7)Waste material is compressed in the rectum and eliminated through the anus
Answer:
The outside of a neuron has more sodium ions while at resting state. When a electrical signal is going to pass through, the sodium channels open up first and the positive sodium ions rush inward making the inner side more positive. This is called action potential.
There is layer of fatty substances called as Myelin Sheath over the course of axons. It helps the electrical signal to be transmitted with a fast pace and efficiently over the course.
Answer:
x(t) = - 6 cos 2t
Explanation:
Force of spring = - kx
k= spring constant
x= distance traveled by compressing
But force = mass × acceleration
==> Force = m × d²x/dt²
===> md²x/dt² = -kx
==> md²x/dt² + kx=0 ------------------------(1)
Now Again, by Hook's law
Force = -kx
==> 960=-k × 400
==> -k =960 /4 =240 N/m
ignoring -ve sign k= 240 N/m
Put given data in eq (1)
We get
60d²x/dt² + 240x=0
==> d²x/dt² + 4x=0
General solution for this differential eq is;
x(t) = A cos 2t + B sin 2t ------------------------(2)
Now initially
position of mass spring
at time = 0 sec
x (0) = 0 m
initial velocity v= = dx/dt= 6m/s
from (2) we have;
dx/dt= -2Asin 2t +2B cost 2t = v(t) --- (3)
put t =0 and dx/dt = v(0) = -6 we get;
-2A sin 2(0)+2Bcos(0) =-6
==> 2B = -6
B= -3
Putting B = 3 in eq (2) and ignoring first term (because it is not possible to find value of A with given initial conditions) - we get
x(t) = - 6 cos 2t
==>
