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vekshin1
3 years ago
12

For beam design, the cross section dimensions of the beam are determined: A. Based on allowable normal stress, but the allowable

shear stress should always be checked to be sure it is not exceeded. B. Based on the allowable shear stress, but the allowable normal stress should always be checked to be sure it is not exceeded. C. Such that both the allowable normal stress and the allowable shear stress are reached at the same time. D. Based on the allowable normal stress. E. The allowable shear stress is not an important design consideration.
Engineering
1 answer:
noname [10]3 years ago
8 0

Answer:

B. Based on the allowable shear stress, but the allowable normal stress should always be checked to be sure it is not exceeded

Explanation:

Shear stress is analyzed to determine the shear forces along the lenght of the beam. This is represented in a shear force diagram. The beam cross sectional design is determined in such a way as to minimize the shear stress. Allowable normal stress should always be checked in a structure if failure is to be prevented.

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5. Which of the following is false about onStep?
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The false statement about onStep is: B. The default number of steps per second is 30.

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2 years ago
Discuss three objectives of Tariff and elaborate on three characteristics of it
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Three objectives of a tariff are

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3 years ago
A ductile hot-rolled steel bar has a minimum yield strength in tension and compression of 350 MPa. Using the distortion-energy a
Ratling [72]

Answer:

Explanation:

From  the given question:

Using the distortion energy theory to determine the  factors of safety  FOS can be expressed  by the relation:

\dfrac{Syt}{FOS}= \sqrt{ \sigma x^2+\sigma  y^2-\sigma x \sigma y+3 \tau_{xy^2}}

where; syt = strength in tension and compression = 350 MPa

The maximum shear stress theory  can be expressed as:

\tau_{max} = \dfrac{Syt}{2FOS}

where;

\tau_{max} =\sqrt{ (\dfrac{\sigma x-\sigma  y}{2})^2+ \tau _{xy^2

a. Using distortion - energy theory formula:

\dfrac{350}{FOS}= \sqrt{94^2+0^2-94*0+3 (-75)^2}}

\dfrac{350}{FOS}=160.35

{FOS}=\dfrac{350}{160.35}

FOS = 2.183

USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{94-0}{2})^2+ (-75)^2

\dfrac{350}{2 FOS}  =88.51

\dfrac{350}{ FOS}  =2 \times 88.51

{ FOS}  =\dfrac{350}{2 \times 88.51}

FOS = 1.977

b. σx = 110 MPa, σy = 100 MPa

Using distortion - energy theory formula:

\dfrac{350}{FOS}= \sqrt{ 110^2+100^2-110*100+3(0)^2}

\dfrac{350}{FOS}= \sqrt{ 12100+10000-11000

\dfrac{350}{FOS}=105.3565

FOS=\dfrac{350}{105.3565}

FOS =3.322

USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{110-100}{2})^2+ (0)^2

\dfrac{350}{2 FOS}  ={ (\dfrac{110-100}{2})^2

\dfrac{350}{2 FOS}  =25

FOS = 350/2×25

FOS = 350/50

FOS = 70

c. σx = 90 MPa, σy = 20 MPa, τxy =−20 MPa

Using distortion- energy theory formula:

\dfrac{350}{FOS}= \sqrt{ 90^2+20^2-90*20+3(-20)^2}

\dfrac{350}{FOS}= \sqrt{ 8100+400-1800+1200}

\dfrac{350}{FOS}= 88.88

FOS = 350/88.88

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USing the maximum-shear stress theory;

\dfrac{350}{2 FOS}  =\sqrt{ (\dfrac{90-20}{2})^2+ (-20)^2

\dfrac{350}{2 FOS}  =\sqrt{ (35)^2+ (-20)^2

\dfrac{350}{2 FOS}  =\sqrt{ 1225+ 400

\dfrac{350}{2 FOS}  =40.31

FOS}  =\dfrac{350}{2*40.31}

FOS = 4.341

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3 years ago
The part of a circuit that carries the flow of electrons is referred to as the?
Oksanka [162]

Answer:

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Explanation:

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