So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
₇N¹⁴ + ₂He⁴ → ₈O¹⁷ + ₁H¹
The superscript for oxygen is 17.
