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3 years ago

Science question below

Chemistry

2 answers:

Shkiper50 [21]3 years ago

7 0

The answer is A because it does

Gwar [14]3 years ago

6 0

It's gotta be A cause of course it occurs in spring since it literally says SPRING tide

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An oxide of phosphorus contains 56.4% phosphorus and 43.6% oxygen. It's relative molecular mass is 220. Find both the empirical

sladkih [1.3K]

Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O

converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5

1 P and 2 oxygens.
PO2 -> the empirical formula

hope this help

7 0

2 years ago

Read 2 more answers

Mixing salt with water is an example of a _________change. *<br> physical change<br> chemical change

SIZIF [17.4K]

Answer:

physical

Explanation:

no chemical reaction is happening

6 0

2 years ago

How many atoms are there in 5.70 mol of Mg

mixer [17]

6.0223 x 10^23 atoms

8 0

2 years ago

What is the gram formula mass of Glycine , NH2CH2COOH

dem82 [27]

N=14
H= 1(5)= 5
C=12(2)=24
O=16(2)=32

= 75

6 0

2 years ago

Draw the best Lewis structure for NH3 by filling in the bonds, lone pairs, and formal charges. (Assign bonds, lone pairs, radica

kiruha [24]

Answer : The Lewis-dot structure of $NH_3$ is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $NH_3$

As we know that hydrogen has '1' valence electron and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $NH_3$ = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on N}=5-2-\frac{6}{2}=0$

$\text{Formal charge on }H_1=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_2=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_3=1-0-\frac{2}{2}=0$

Hence, the Lewis-dot structure of $NH_3$ is shown below.

3 0

2 years ago