There are only 2 organic compounds present, C2H6 and CH4. The rest are all inorganic compounds.
Answer: im pretty sure it's electrical.
Answer:
A) 8.08*10^-10 cm^-1
B) 1.27 * 10^-5
Explanation:
A) PERMEABILITY OF THE MEMBRANE to the material = K * D/(dx) ---- (1)
K = J / (Cl - Cr )
= 0.234 * 10^-12 / (2.3*10^-6 M - 0 )
= 10 *10^-6 M
dx = 10*10^-6 m * 100 cm
= 10 *10^-4 cm
D = 0.8 * 10^-5 cm^2s^-1
input the calculated values into equation 1
permeability of the membrane = 8.08*10^-10 cm^-1
B) equivalent relative area available for the diffusion of the material
at thickness of membrane = 10*10^-6 m
can be calculated using this relation = ---------- (2)
flux = 0.234 * 10^-12 mol.cm^-2.s^-1
thickness = 10*10^-4 cm
diffusion coefficient = 0.8 * 10^-5 cm^2.s
Cl = 2.3*10^-6 m
input the above values into equation 2
equivalent relative area available for the diffusion of the material
= 1.27 * 10^-5
The density of the stone is 5 because the formula is mass/volume and the volume is 5 and the mass is 25
A) The acids only slightly dissociate and readily undergo reverse reaction.
for example:
acetic acid
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq)
nitrous acid
HNO₂(aq) ⇄ H⁺(aq) + NO₂⁻(aq)
carbonic acid
H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq)
HCO₃⁻(aq) ⇄ H⁺(aq) + CO₃²⁻(aq)