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galben [10]
3 years ago
12

The reduction of iodine gas at a constant current of 1.50 amperes for 12.0 hours would result in how many grams of I–? (1 farada

y = 96,500 coulombs)
Chemistry
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

85.2 grams.

Explanation:

Look up the relative atomic mass data on a modern periodic table.

  • Iodine: 126.904 g/mol.

The Faraday's Constant F gives the size of the charge (in Coulombs) on one mole of electrons. Also, keep in mind that \rm 1 \; Ampere = 1\; Coulomb/ second.

Charge supplied to the iodine:

\begin{aligned}Q &= I \cdot t = \rm 1.50 \; C \cdot s^{-1} \times (12.0 \times 3600) \; s\\ &= \rm 64800\; C\end{aligned}

How many moles of electrons does that much charge correspond to?

\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} = \rm \frac{64800\; C}{96500\; C\cdot mol^{-1}}= 0.67150\; mol\end{aligned}.

Consider the reduction half-equation for iodine:

\rm I_2 + 2 \; e^{-} \to 2 \; I^{-}.

Divide both sides by 2 to make sure that the coefficient in front of \rm e^{-} is equal to 1.

\displaystyle \rm \frac{1}{2}\; I_2 + e^{-} \to I^{-}.

The ratio between the coefficient in front of \rm e^{-} and that of \rm I^{-} is equal to 1. In other words, while gaseous iodine is in excess, each mole of electrons will produce one mole of iodine ions.

\rm 0.67150\; mol of electrons will produce \rm 0.67150\; mol of iodine ions.

The mass of one mole of iodine ions is approximately the same as that of one mole of iodine atoms.

M(\mathrm{I^{-}}) \approx M(\mathrm{I})= \rm 126.904\; g\cdot mol^{-1}.

m(\mathrm{I}^{-}) = n \cdot M \approx \rm 85.2\; g.

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Answer:

pH = 3.95

Explanation:

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3.77 = pka + log₁₀ [0.50] / [0.50]

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Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

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[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

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A sugar crystal contains approximately 1.4×1017 sucrose (C12H22O11) molecules. What is its mass in milligrams? Express using 2 s
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Answer:

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4.1 The Chemical Equation

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Define chemical equation.

Identify the parts of a chemical equation.

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This is an example of a chemical equation, which is a concise way of representing a chemical reaction. The initial substances are called reactants, and the final substances are called products.

Unfortunately, it is also an incomplete chemical equation. The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. If we count the number of hydrogen atoms in the reactants and products, we find two hydrogen atoms. But if we count the number of oxygen atoms in the reactants and products, we find that there are two oxygen atoms in the reactants but only one oxygen atom in the products.

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