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4 years ago

In the formula Work=Force X Distance, what happens to the amount of work done if either Force or Distance is increased?

Physics

1 answer:

AfilCa [17]4 years ago

6 0

Explanation:

If force or distance is increased, then amount of workdone will also increase.

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A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevat

WINSTONCH [101]

Answer:

The magnitude of the acceleration of the elevator is 0.422 m/s²

Explanation:

Lets explain how to solve the problem

Due to Newton's Law ∑ Forces in direction of motion is equal to mass

multiplied by the acceleration

We have here two forces 460 N in direction of motion and the weight

of the person in opposite direction of motion

The weight of the person is his mass multiplied by the acceleration of

gravity

→ W = mg , where m is the mass and g is the acceleration of gravity

→ m = 45 kg and g = 9.8 m/s²

Substitute these values in the rule above

→ W = 45 × 9.8 = 441 N

The scale reads 460 N

→ F = 460 N , W = 441 N , m = 45 kg

→ F - W = ma

→ 460 - 441 = 45 a

→ 19 = 45 a

Divide both sides by 45

→ a = 0.422 m/s²

<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>

4 0

4 years ago

A car displaced 45 north of east by 10km

Amanda [17]

Answer:

coooooooooooooooooool

Explanation:

hab a good day :)

5 0

3 years ago

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The triceps muscle in the back of the upper arm extends the forearm.

iren [92.7K]

To solve this problem it is necessary to apply the concepts related to Torque as a function of Force and distance. Basically the torque is located in the forearm and would be determined by the effective perpendicular lever arm and force, that is

$\tau = F \times r$

Where,

F = Force

r = Distance

Replacing,

$\tau = 2*10^3*0.03$

$\tau = 60N\cdot m$

The moment of inertia of the boxer's forearm can be calculated from the relation between torque and moment of inertia and angular acceleration

$\tau = I \alpha$

I = Moment of inertia

$\alpha$ = Angular acceleration

Replacing with our values we have that

$I = \frac{\tau}{\alpha}$

$I = \frac{60}{120}$

$I = 0.5kg\cdot m^2$

Therefore the value of moment of inertia is $0.5kg\cdot m^2$

8 0

3 years ago

Which is an example of a chemical change?

Mashutka [201]

Answer:

Burning wax

Explanation:

because in burning, wax reacts with oxygen present in the surrounding and forms carbon dioxide and ash

7 0

4 years ago

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A 1200 kg car traveling at 60 mph quickly brakes to a halt. The kinetic energy of the car is converted to thermal energy of the

ololo11 [35]

Answer:

ΔT = 59.9 ° C

Explanation:

For this exercise the brake energy is totally converted into heat

Let's calculate the vehicle energy

K = ½ m v²

Let's reduce the units to the SI system

v = 30 mph (1609.34 m / mile) (1h / 3600s) = 13.41 m / s

Em = K = ½ 1200 13.41²

K = 1.079 105 J

All this energy is transformed into heat

Em = Q

The expression for heat is

Q = m $c_{e}$ ΔT

ΔT = Q / m $c_{e}$

The specific heat of iron is $c_{e}$ = 450 J / Kg ºC

ΔT = 1,079 105 / (4.0 450)

ΔT = 59.9 ° C

8 0

4 years ago

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