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3 years ago

What is the value of free falling acceleration?

Physics

2 answers:

worty [1.4K]3 years ago

8 0

On or near the Earth's surface, without air resistance,
it's 9.81 meters per second². (32.2 feet per second²)

vekshin13 years ago

3 0

Freely falling acceleration is the acceleration due to gravity 'g'. It's value is 9.8 N, but for convenience it is taken as 10 N.

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Microwelds are formed where_______

Shtirlitz [24]

The correct answer is B

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3 years ago

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A solid sphere rolls along a horizontal, smooth surface at a constant linear speed without slipping. What is the ratio between t

Pavlova-9 [17]

The ratio of the rotational kinetic energy about the center of the sphere and the total kinetic energy of the sphere is 2/7.

<h3>What is the rotational kinetic energy of a sphere?</h3>

The rotational kinetic energy of the sphere is directly proportional to the square of angular acceleration.

$K = \dfrac 12 I\omega ^2$

Where,

$I$ = rotational inertia of sphere = 2/5MR²

Where $M$ is the mass of the sphere and $R$ is the radius of the sphere,

ω = angular acceleration of sphere = V/R

Where $V$ is the speed of the sphere.

So,

K = 1/2 × 2/5MR² × V²/R²

K = MV²/5

The translational kinetic energy of the sphere,

$K' = \dfrac 12 MV^2$

The total kinetic energy of the sphere,

$K_t = K + K'$

So,

$K_t= \dfrac {MV^2}5 +\dfrac { MV^2}2\\\\K_t= \dfrac {7MV^2}{10}$

Thus the Ratio of rotational kinetic energy to total kinetic energy,

$\dfrac KK_t = \dfrac {\dfrac {MV^2}{5} }{ \dfrac {7MV^2}{10}}\\\\\dfrac KK_t = \dfrac 15 \times \dfrac { 10}7\\\\\dfrac KK_t= \dfrac 27$

Therefore, the ratio of the rotational kinetic energy about the center of the sphere and the total kinetic energy of the sphere is 2/7.

Learn more about rotational kinetic energy:

brainly.com/question/14611300

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2 years ago

I am primarily made of calcium. I protect and act as camouflage. I can be found as a filler in most household spices. What am I?

schepotkina [342]

Answer:

Explanation:

Bones?

Bones are primarily made of calcium. Also, they protect the body, which is pretty much obvious. They also act as camouflage.

The only but I have is, can they be found as a filler in most household?

Asides that, bones pretty much fits in to the answer.

8 0

3 years ago

Why do you think the area swept out by a planet in a given period of time remains constant, even as the planet speeds up and slo

Levart [38]

Not sure this is entirely right but hey why not, right. <span> A planet orbiting a star orbits in an ellipse. Sometimes it's closer to the star and sometimes it's further. When it's closer to the star, the gravity on the planet from the star is stronger, so the planet speeds up. The area the planet sweeps over is equal because when it speeds up the length covered along the orbital path is greater, but it is also closer to the star, and that dimension is decreased. And because of our very intelligently designed and organized universe, these two factors cancel each other out perfectly </span>
<span>Hope I helped in some way!

</span>

6 0

3 years ago

Read 2 more answers

Wegut.

AVprozaik [17]

We/Wm = ge/gm = 120N/1.2N

gm = ge/100 = 0.1 m/s^2

density = mass/volume = 3M/(4pir^3)

Re-arranging this equation, we get

M/r^2 = (4/3)×pi×(density)×r

From Newton's universal law of gravitation, the acceleration due to gravity on the moon gm is

gm = G(M/r^2) = G×(4/3)×pi×(density)×r

Solving for density, we get the expression

density = 3gm/(4×pi×G×r)

= 3(0.1)/(4×3.14×6.67×10^-11×2.74×10^6)

= 130.6 kg/m^3

6 0

3 years ago