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IgorC [24]
3 years ago
8

An easy way to assign the number of d-electrons (the “d count”) in a transition metal ion is to first look at the periodic t

able and take note of which group the element is in. For example, chromium is in Group 6, so elemental chromium has 6 valence electrons. Therefore, chromium 3+ has three 3d-electrons. What is the number of 3d-electrons in cobalt 3+?
Chemistry
1 answer:
Lorico [155]3 years ago
6 0
Chromium is in Group 6, so elemental chromium has 6 valence electrons. Therefore, chromium 3+ has three 3d-
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What was the key design change for hfc-134a a/c systems versus CFC 12 a/c systems
BabaBlast [244]
Answer is: key design change for HFC-134a A/C systems versus CFC-12 A/C systems was quick couple service fitting and that design reduce venting and mixing of refrigerants during service.

<span> Level of contamination is also reduced and the emission of refrigerants and greenhouse gases (sulfur dioxide, carbon dioxide) is also reduced.</span>

6 0
3 years ago
Write a balanced chemical equation for the incomplete combustion of gaseous ethane (C2H6). What is the sum of the coefficients i
Delicious77 [7]

Answer:

C2H6 +02 ===>Co2 + H20.

Explanation:

7 0
3 years ago
HELP PLEASE WILL GIVE BRAINLIEST
Crank

Answer:

Option D. Al is above H on the activity series.

Explanation:

The equation for the reaction is given below:

2Al + 6HBr —> 2AlBr₃ + 3H₂

The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.

From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.

Considering the equation given above, Al is higher than H in the activity series. Thus, the reaction will proceed as illustrated by the equation.

Therefore, we can conclude that the reaction will only occur if Al is higher than H in the activity series.

4 0
3 years ago
Which of these compounds are oxidizing agents?
elena55 [62]

i guess its e) Mn (VII)

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6 0
3 years ago
Read 2 more answers
How many molecules in each sample?<br><br> 64.7 g N2<br> 83 g CCl4<br> 19 g C6H12O6
lilavasa [31]

Answer:

  • 1.39x10²⁴ molecules N₂
  • .25x10²³ molecules CCl₄
  • 6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:

  • 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
  • 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
  • 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:

  • 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
  • 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
  • 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
3 0
3 years ago
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