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IgorC [24]
3 years ago
8

An easy way to assign the number of d-electrons (the “d count”) in a transition metal ion is to first look at the periodic t

able and take note of which group the element is in. For example, chromium is in Group 6, so elemental chromium has 6 valence electrons. Therefore, chromium 3+ has three 3d-electrons. What is the number of 3d-electrons in cobalt 3+?
Chemistry
1 answer:
Lorico [155]3 years ago
6 0
Chromium is in Group 6, so elemental chromium has 6 valence electrons. Therefore, chromium 3+ has three 3d-
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A compound ‘X’ is used for drinking, has pH =7.Its acidified solution undergoes decomposition in presence of electricity to prod
umka21 [38]

Answer:

X = Water (H2O) ; Y = Hydrogen ; Z = Oxygen

Explanation:

2(H2O) -------> 2H2 + O2

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How does trace evidence end up transferring to the crime scene, suspect, or victim? Discuss some of the ways that this might hap
disa [49]
Trace evidence can end up transferring to the crime scene through Locard's Exchange Principle, which states that whenever two things come into contact with one another, there is an exchange of physical material A.K.A evidence. This exchange is most often done through physical contact, such as a struggle or a suspect attempting to hide evidence or alter the crime scene. It can even involve a suspect's shirt sleeve brushing against some wet paint.

I hope I helped!
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strojnjashka [21]

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Explanation:

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3 years ago
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The average kinetic energy of gas particles depends on which factor?
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4 0
3 years ago
Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de
nignag [31]

Answer:

\%m/m=14\%

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14

Which is also the by-mass fraction and in percent it turns out:

\%m/m=0.14*100\%\\\\\%m/m=14\%

Best regards!

6 0
3 years ago
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