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mart [117]
4 years ago
9

Draw two five carbon rings that share an atom.

Chemistry
1 answer:
Katena32 [7]4 years ago
8 0
Here’s the steps to do this & then a photo! Hope this helps!


Draw your electron rings. The circle with the "C" is a representative nucleus, so now you'll need to indicate the electron orbitals. The number of rings you need is to tied to the number of electrons you have. Carbon has 6 electrons. Since each ring has a maximum number of electrons that can be pictured, you'll have to do some math. The first ring can have a maximum of 2 electrons, the second ring a maximum of 8, the third ring a maximum of 18, etc. Carbon has 6 electrons, so you'll need to draw two concentric rings.
Draw your electrons. You can do this a couple different ways. Some people just draw circles on the rings and fill them in. In this case, you would draw 2 on the first ring and 5 on the second ring. The best way to draw electrons is to draw them as circles with minus signs inside. This indicates not only that they are electrons, but helps remind the viewer that electrons contain a negative charge.

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The density of a saline (salt) solution is 1.27 g/mL. What is the mass of 326 milliliters of the solution?
zlopas [31]

Answer:

thx for the points

Explanation:

7 0
3 years ago
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PLZ HELP. Write and balance the following chemical equations:
zubka84 [21]

Answer:

No they form nitrogen oxide which can be poisonous to some species but depending on the amount of nitrogen it can be harmful to everything living. Such as if you put it with a plant that had low nitrogen levels then there would be no carbon dioxide to filter.

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3 years ago
A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr?
Umnica [9.8K]

Answer:

b)4.46 L/hr

Explanation:

To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)

<em>mL to L:</em>

1.24mL/s * (1L / 1000mL) = 0.00124L/s

<em>seconds to hours:</em>

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Right answer is:

<h3>b)4.46 L/hr </h3>

3 0
3 years ago
4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.
Elodia [21]

Answer:

Y=48.6\%

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

2Cu+O_2\rightarrow 2CuO

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO}  =0.078gCuO

Therefore, the percent yield is:

Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%

Best regards.

6 0
4 years ago
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anyanavicka [17]
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