1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BartSMP [9]
3 years ago
14

Suppose you figured resistance of a color-coded resistor is 100 ± 5 ohms. You did the Ohms law experiment and measured resistanc

e of the same resistor. You found the measured value is 92 ± 4 ohms. How would you compare the two values? Choose all that are correct. Group of answer choices I will find the percent difference between 100 and 92 ohsm and conclude that they are different I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the numbers are different, I conclude that they are different within uncertainty I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty. I will draw a dot and whisker plot for both. Since they overlap, I can conclude that they are the same within uncertaitny
Physics
1 answer:
aivan3 [116]3 years ago
5 0

Answer:

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

Explanation:

The value of all physical measurement has an uncertainty, so it is within a range of values, in this case we must compare the range of values ​​of the resistors

The nominal value is 100 ± 5 Ω

therefore its range of possible values ​​is between

             95 <= R <= 105

For the experimentally measured value

          88 <= R <= 96

as the values ​​overlap we must conclude that they are the same.

When reviewing the different options we have two statements that are correct

* I will look at the range of both, such as 100-5 = 95 and 94+4=98. Since the ranges overlap, I can conclude that they are the same within uncertainty.

* I willl draw a dot-and-whisker plot for both. Since they overlap, I can conclude that they are equal within the uncertainty

You might be interested in
In the shadow of a tree with a dense, leafy canopy, one sees a number of light spots. Surprisingly, they all appear to be circul
Bad White [126]

The characteristics of the diffraction phenomenon allow to find the result for the shape of the points of light that you pass the tree is:

  • The shape of the dots is circular because it is in the range of far-field diffraction.

Diffraction is the phenomenon where the undulatory part of the light becomes evident, it is the interference of the waves that make up each ray of light, for this phenomenon to occur it must be fulfilled that the wavelength is of the order of the space where pass the light.

In the leafy tree it has many leaves, but there are spaces between them, some of these spaces are small and it fulfills the diffraction condition, therefore we see bright spots and not a continuous shadow.

Diffraction can be classified depending on the distance to the observer:

  • Near field or fresnel. In this case the distance from the observer is small and we can see the shape of the object that creates the diffraction.
  • Far field or Fraunhoger. In this case the distance between the obstacle (leaves) and the person is great, here the information on the shape of things is lost and we have two observable forms. Lines for the case of slits and circles for the case of objects with a closed shape.

In this case, the distance from the leaves to the observer is large, therefore we are in the case of far-field diffraction and since the edge of the leaves that forms the diffraction is closed, the observable shape is a circle.

In conclusion using the characteristics of the diffraction phenomenon we can find the result for the shape of the points of light that pass the tree is:

  • The shape of the dots is circular because it is in the range of far-field diffraction.

Learn more about diffraction here:  brainly.com/question/20140459

8 0
2 years ago
Need help in Psychology. Please help! Which of the following statements best describes abductive reasoning? A.I think,therefore
Pepsi [2]
The "D) People perceive objects as a whole" statement best describes an abductive reasoning. The abductive reasoning often has incomplete information as the base of its reasoning and the conclusion for this type of reasoning is not absolute. There will always be additional pieces of evidence and factors that could change the conclusion of this reasoning. Therefore<span> D statement is the most suitable answer.</span>
5 0
3 years ago
An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area A= 1.65 m^2

We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

Where,

A = area

E = electric field

Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
3 years ago
"The ________ method can determine whether a string contains a value that can be converted to a specific data type before it is
dem82 [27]

Answer:

The method to determine whether a string contains a value that can be converted to a specific data type before it is converted to that data type

Explanation:

The Java string includes () method to check whether a particular sequence of character is the part of given sub string or not.

One string contain another string in Java or not.

The indexof() to check the string and substring in java

Hence java string include () method to check  whether a string contains a value that can be converted to a specific data type before it is converted to that data type

6 0
3 years ago
Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

t = time = 3 [s]

11 = 5 + a*3\\6=3*a\\a= 2[m/s^{2} ]

4 0
3 years ago
Other questions:
  • .... Answer this... ​
    15·1 answer
  • A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the condu
    15·1 answer
  • An ice skater weighs 500 [N]. He is coasting to the right at a constant velocity of 2 [m/s]. Assume
    13·1 answer
  • I REALLY NEED HELP!!!!
    11·1 answer
  • Cecily is inflating her bicycle tyre with the pump below. When she pushes the plunger down, it is doing work against the gas. Th
    13·1 answer
  • 56. What is the range of magnitudes that can be attained from the
    9·1 answer
  • Join dua-odmb-pwp meet plßsssssss​
    12·1 answer
  • How would the period Of the pendulum different from an equivalent one on earth​
    7·1 answer
  • Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.60 cm from the axis to equal
    5·1 answer
  • True or false: An object’s weight can change, but its mass remains the same. True False
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!