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Jet001 [13]
3 years ago
10

Which of the following places the elements in the correct order of increasing first ionization energy?

Chemistry
2 answers:
bazaltina [42]3 years ago
4 0

D. Be, Mg, Ca

__________

Simora [160]3 years ago
4 0

Answer : The correct option is A.

Explanation :

Ionization energy : It is defined as the less amount of energy is required to remove the electron from their valence shell.

In general,

As we go down in a periodic table, the ionization energy decreases and as we across a period in a periodic table, the ionization energy increases.

In Case of P, S, Cl, the ionization energy increases as we are moving from left to right.

In Case of F, O, N, the ionization energy decreases as we are moving from right to left.

In Case of Cl, S, P, the ionization energy decreases as we are moving from right to left.

In Case of Be, Mg, Ca, the ionization energy decreases as we are moving from top to bottom.

Therefore, the correct answer is A.



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1. CH4 + 2O2 → CO2 + 2H2O
2. 10.80 degrees celsius
3. 45,187 J
4. 7,506 J
<span>5. 52,693 J </span>
6 0
3 years ago
If you begin with 2.7 g Al and 4.05 g Cl2, what mass of AlCl3 can be produced?
Tresset [83]
<span>atomic weights: Al = 26.98, Cl = 35.45 In this reaction; 2Al = 53.96 and 3Cl2 = 212.7 Ratio of Al:Cl = 53.96/212.7 = 0.2537 that is approximately four times the mass Cl is needed. Step 2: (a) Ratio of Al:Cl = 2.70/4.05 = 0.6667 since the ratio is greater than 0.2537 the divisor which is Cl is not big enough to give a smaller ratio equal to 0.2537. so Cl is limiting (b)since Cl is the limiting reactant 4.05g will be used to determine the mass of AlCl3 that can be produced. From Step 1: 212.7g of Cl will produce 266.66g AlCl3 212.7g = 266.66g 4.05g = x x = 5.08g of AlCl3 can be produced (c) Al:Cl = 0.2537 Al:Cl = Al:4.05 = 0.2537 mass of Al used in reaction = 4.05 x 0.2537 = 1.027g Excess reactant = 2.70 - 1.027 = 1.67g King Leo · 9 years ago</span>
8 0
3 years ago
If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present
qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

Molarity = mole of solute/Volume of solution.

0.25 = mole of MgCl2 /8

Cross multiply to express in linear form

Mole of MgCl2 = 0.25 x 8

Mole of MgCl2 = 2 moles

Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

4 0
3 years ago
What is the empirical formula of propene CH3 CH2 CH2​
kiruha [24]

Answer:

<u>CH</u>

Explanation:

Molecular formula of propene : <u>C₃H₆</u>

Take the HCF of carbon and hydrogen atoms :

  • 3 = 3
  • 6 = 2 x 3

Then, we can write the formula as :

  • 3CH
  • This means there are 3 moles present

Empirical Formula :

  • Molecular Formula / No. of moles
  • C₃H₆ / 3
  • <u>CH</u>

<u></u>

The empirical formula of propene is <u>CH</u>

6 0
1 year ago
Which of these is a characteristic of science?
Ivahew [28]

D. It gives the same results when experiments are repeated

3 0
3 years ago
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