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anygoal [31]
3 years ago
8

Proteoglycans are part of the extracellular matrix; they provide structure, viscosity and lubrication, and adhesiveness. They ar

e composed of proteins conjugated to carbohydrate components called glycosaminoglycans. The glycosaminoglycan component makes up the majority of the mass of a proteoglycan. Which of the following are possible components of glycosaminoglycans? Select all that apply. Determine which of the following statements about glycosaminoglycans are true. There is more than one true statement; select all the true statements. Dermatan sulfate and keratan sulfate are examples of glycosaminoglycans. Because glycosaminoglycans consist of only two residues, they generally have low molecular weights. Dextran is an example of a glycosaminoglycan. Glycosaminoglycans are heteropolysaccharides composed of repeating disaccharide units. The amino groups of the amino sugar derivatives provide a positive charge that offsets the negative charges from the sulfate or carboxylate groups.
Chemistry
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

Here’s what I find.

Explanation:

A. Dermatan sulfate and keratan sulfate are examples of glycosaminoglycans (GAGs). TRUE.

They are both long unbranched polymers in which the repeating unit is a disaccharide consisting of a uronic sugar and an N-acetylated amino sugar.

D. Glycosaminoglycans are heteropolysaccharides composed of repeating disaccharide units. TRUE.

A heteropolysaccharide contains two or more monosaccharides, and GAGs contain  a hexoseuronic acid and an N-acetylhexosamine.

B. FALSE. GAGs consist of only two residues, but they are the disaccharide units in a polymer chain that has a molecular weight greater

than 2.5 × 10^6 u.

C. FALSE. Dextran is a polysaccharide of glucose.

E. FALSE. The amino groups in the amino sugars are acetylated, so they are acetamide derivatives. Amides (Kb = 10^-15) are much less basic than amines (Kb = 10^-5), so they are not protonated.

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Calculate [H+] for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral.
vesna_86 [32]

Answer:

<em>Part A: </em>10.7.

<em>Part B: </em>2) the solution is basic.

<em>Part C: </em>5.9.

<em>Part D: </em>1) the solution is acidic.

<em>Part E: </em>8.1.

<em>Part F: </em>2) the solution is basic.

Explanation:

<em>Part A [OH−]= 4.5×10−4 M . Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>[OH⁻] = 4.5×10⁻⁴ M. </em>

<em>∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(4.5×10⁻⁴  M) = 2.22 × 10⁻¹¹ M.</em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(2.22 × 10⁻¹¹) = 10.65 ≅ 10.7.</em>

<em></em>

Part B 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  

The solution is basic, because the pH is higher than 7.

<em>Part C [OH⁻]= 7.7×10⁻⁹ M . Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>[OH⁻] = 7.7×10⁻⁹ M. </em>

<em>∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(7.7×10⁻⁹ M) = 1.29 × 10⁻⁶ M.</em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(1.29 × 10⁻⁶) = 5.88 ≅ 5.9.</em>

<em>Part D 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  </em>

The solution is acidic, because the pH is lower than 7.

<em>Part E A solution in which [OH−] is 140 times greater than [H+]. Express your answer using two significant figures.  </em>

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

<em>∵  [OH⁻] = 140[H₃O⁺]</em>

<em>∴ [H₃O⁺](140[H₃O⁺]) = 10⁻¹⁴. </em>

<em>∴ 140 [H₃O⁺]² = 10⁻¹⁴. </em>

<em>[H₃O⁺]² = 10⁻¹⁴/ 140 = 7.14 x 10⁻¹⁷.</em>

<em>∴ [H₃O⁺] = √(7.14 x 10⁻¹⁷) = 8.45 x 10⁻⁹ M.</em>

<em></em>

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(8.45 x 10⁻⁹) = 8.07 ≅ 8.1.</em>

<em>Part F 1) the solution is acidic 2) the solution is basic 3) the solution is neutral</em>

<em></em>

The solution is basic, because the pH is higher than 7.

3 0
3 years ago
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Arisa [49]
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I’m pretty sure hope you get it right!
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Which statement best describes the effect of low ionization energies and low electronegativities on metallic bonding?
kramer
The statement that best describes the effect of low ionization energies and low electronegativities on metallic bonding is the first one - the valence electrons are easily delocalized. 
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A typical refrigerator is kept at 4˚C, and a soda can has a pressure of
ss7ja [257]

Answer: The new pressure will be 1.42 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=1.18atm\\T_1=4^0C=(4+273)K=277K\\P_2=?\\T_2=60^0C=(60+273)K=333K

Putting values in above equation, we get:

\frac{1.18}{277}=\frac{P_2}{333}\\\\P_2=1.42

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7 0
3 years ago
1. What did Henri Becquerel discover about<br> radiation emitted from uranium salts?
Dmitriy789 [7]

Explanation:

When Henri Becquerel investigated the newly discovered X-rays in 1896, it led to studies of how uranium salts are affected by light. By accident, he discovered that uranium salts spontaneously emit a penetrating radiation that can be registered on a photographic plate.

6 0
3 years ago
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