Answer:
Well I don't think there is a specific answer for that, but a lot of under the age children do drink and smoke,because these days,their parents either don't care, and some just don't know about it. Many kids drink and smoke these days and I don't think there is a on point percentage.
Explanation: Hope this helps and have a good day!!!
The options are missing and they are;
A) the electric force increases because the balloon loses its charge.
B) the electric force increases because the distance increases.
C) the electric force decreases because the distance increases.
D) the electric force decreases because his hair loses its charge.
Answer:
Correct answer is option C - the electric force decreases because the distance increases.
Explanation:
The formula for electric force is;
F = k•q1•q2/r²
Where;
K is coulombs constant
q1 and q2 are particle charges
r is distance
So,looking at the formula given earlier, if we increase the distance, the denominator will increase and thus the Force will decrease.
So the correct option is option C
To lift the bag straight up takes (F · D) = (45 · 1.2) = 54 joules of energy (work).
Moving the bag horizontally 'across' gravity requires no work.
It doesn't matter how far.
Answer:
(a) Since net charge remains same,after immersion Q is same
(b) I. 14.56pF ii. 3.05V
(c) ΔU = 5.204nJ
Explanation:
a)
C = kεA/d
k=1 for air
ε is 8.85x10-12F/m
A = .0025m2
d = .125m
C = 8.85x10-12x.0025/.125 = 1.77x10-13F = 0.177pF
Q = CV = .177pF * 244V = 43.188pC
Since net charge remains same,after immersion Q is same
b)
C = kεA/d, for distilled water k is approx. 80
Cwater = Cair x k
=0.177pF x 80 = 14.16pF
Q is same and C is changed V=Q/c holds. where Q is still 43.188pC and C is now 14.16pF, so V = 43.188pC/14.16pF = 3.05V
c) Change in energy: ΔU = Uwater - Uair
Uwater = Q2/2C = (43.188)2/2x.177pF = 5.27nJ
Uair = Q2/2C = (43.188)2/2x14.16pF = 0.066nJ
ΔU = 5.204nJ
