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tatuchka [14]
3 years ago
14

if u connect 3 resistors, having values 2ohm, 3ohm, 5ohm in parallel, will the value of total resistance of will be 2ohm or grea

ter than 5ohm or lie between 2ohm and 5oh? EXPLAIN
Physics
2 answers:
Tju [1.3M]3 years ago
4 0
<span>If u want only WHether the total resistance is less than 2 or less than 5 or more than 5 ohms:  there is a Simple way.

When you connect resistances in parallel, resultant resistance is always smaller than all of them. So it is less than 2 ohms</span>.

irina1246 [14]3 years ago
4 0
\frac{1}{3}+\frac{1}{2}+\frac{1}{5}=\\&#10;\frac{10}{30}+\frac{15}{30}+\frac{6}{30}=\\&#10;\frac{31}{30}\\\\&#10;R_t=\frac{30}{31} \ \Omega\approx0.97\ \Omega
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What is Newton’s second law of motion
ddd [48]

"<em>F = dP/dt. </em> The net force acting on an object is equal to the rate at which its momentum changes."

These days, we break up "the rate at which momentum changes" into its units, and then re-combine them in a slightly different way.  So the way WE express and use the 2nd law of motion is

"<em>F = m·A.</em>  The net force on an object is equal to the product of the object's mass and its acceleration."

The two statements say exactly the same thing. You can take either one and work out the other one from it, just by working with the units.

8 0
3 years ago
Read 2 more answers
Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to
Andrej [43]

(a) 3.1\cdot 10^7 J

The total mechanical energy of the space probe must be constant, so we can write:

E_i = E_f\\K_i + U_i = K_f + U_f (1)

where

K_i is the kinetic energy at the surface, when the probe is launched

U_i is the gravitational potential energy at the surface

K_f is the final kinetic energy of the probe

U_i is the final gravitational potential energy

Here we have

K_i = 5.0 \cdot 10^7 J

at the surface, R=3.3\cdot 10^6 m (radius of the planet), M=5.3\cdot 10^{23}kg (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J

At the final point, the distance of the probe from the centre of Zero is

r=4.0\cdot 10^6 m

so the final potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J

So now we can use eq.(1) to find the final kinetic energy:

K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J

(b) 6.3\cdot 10^7 J

The probe reaches a maximum distance of

r=8.0\cdot 10^6 m

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

K_f = 0

At that point, the gravitational potential energy is

U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J

So now we can use eq.(1) to find the initial kinetic energy:

K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J

3 0
2 years ago
A potential energy function is given by u(x)=(3.00n)xâ(1.00n/m2)x3. at what position or positions is the force equal to zero?
qwelly [4]

I believe the correct form of the energy function is:

u (x) = (3.00 N) x + (1.00 N / m^2) x^3

or in simpler terms without the units:

u (x) = 3 x + x^3

Since the highest degree is power of 3, therefore there are two roots or solutions of the equation.

 

Since we are to find for the positions x in which the force equal to zero, u (x) = 0, therefore:

3 x + x^3 = u (x)

3 x + x^3 = 0

Taking out x:

x (3 + x^2) = 0

So one of the factors is x = 0.

 

Finding for the other two factors, we divide the two sides by x and giving us:

x^2 + 3 = 0

x^2 = - 3

x = sqrt (- 3)

x = - 1.732 i, 1.732 i

 

The other two roots are imaginary therefore the force is only equal to zero when the position is also zero.

 

Answer:

x = 0

5 0
3 years ago
Which of the following statements best describes the method of energy conservation known as cogeneration?
Mazyrski [523]

Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

6 0
2 years ago
In Wagner’s opera Das Rheingold, the goddess Freia is ransomed for a pile of gold just tall enough and wide enough to hide her f
Vesna [10]

Answer:

Price=$7×10⁷

Explanation:

Step 1: Estimate the volume of the pile,

Step 2: Multiply it by the density to get its mass

Step 2: Then multiply the mass by the price per gram to get the total price

So

The average pile dimensions are=45.7×45×172.7

V=3.6*10^{5}cm^{3}\\  m_{g}=V_{p}=3.6*10^{5}*19.3=7*10^{6}g\\

Price=m×$10

Price=(7×10⁶)×$10

Price=$7×10⁷

5 0
3 years ago
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