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jekas [21]
3 years ago
7

Two planes take off from the same airport at the same time using different runways. One plane travels on a bearing Upper S 14 de

grees Upper W at 440 miles per hour. The other plane travels on a bearing Upper N 75 degrees Upper W at 420 miles per hour. How far are the planes from each other 3 hours after​ takeoff?
Physics
1 answer:
Mashcka [7]3 years ago
6 0

Answer:

 Let's imagine this is the diagram for the question,

                 •    

3*440=       /  |

               /     |

1320mi  ↑       |

           ↑         ↓

          /           ↓

        /             |

      • ) 89⁰     |

       \              |   "x" miles

         \            ↑

           \          ↑

            ↓         |

              ↓       |      

3*420=      \     |

1260 mi      \   |

                        •

From the Cosine Rule:  x² = y² + z² - 2 y z cos X⁰

x² = 1320² + 1260² - 2 * 1320 * 1260 * cos 89⁰ =  

1742400 + 1587600 - 3326400 * cos 89⁰ = 3271946315  

x ≈ 1809 mi

Hence, the planes are 1809 miles from each other 3 hours after​ takeoff?

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Answer:

v = 24 m/s, rightwards

Explanation:

Given that,

The mass of TBT explosive = 5 kg

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The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,

5\times 0=2\times (-36)+3\times v\\\\-72=-3v\\\\v=24\ m/s

So, the final speed of the remaining piece is 24 m/s and it is in the right direction.

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Oksanka [162]

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A gas in a cylinder expands from a volume of 0.110 m³ to 0.320 m³. heat flows into the gas just rapidly enough to keep the press
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80000 Joule is the change in the internal energy of the gas.

<h3>In Thermodynamics, work done by the gas during expansion at constant pressure:</h3>

ΔW = -pdV

ΔW = -pd (V₂ -V₁)

ΔW = - 1.65×10⁵ pa (0.320m³ - 0.110m³)

     = - 0.35×10⁵ pa.m³

     = - 35000 (N/m³)(m³)

     = -35000 Nm

ΔW = -35000 Joule

Therefore, work done by the system = -35000 Joule

<h3>Change in the internal energy of the gas,</h3>

ΔV = ΔQ + ΔW

Given:

ΔQ = 1.15×10⁵ Joule

ΔW = -35000 Joule

ΔU = 1.15×10⁵ Joule - 35000 Joule

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Therefore, the change in the internal energy of the gas= 80000 Joule.

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3 0
2 years ago
A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve
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use the formula

v= u+ at

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4 0
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