Question

A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km.At the bottom of the dive, the pilot has a speed of 0.20 km/s which at that instant is notchanging. What force does the plane exert on the pilot?

Answer 1

Answer:

 Force plane exert on pilot  = 4270 N

Explanation:

first convert radius and speed to ms

using formula from force we know that

mass = weight/ gravity =  700 N/ 9.8N/kg=  71.4 kg

Fc=  N-mg

N= Fc+ mg                  As Fc = mv²/R

N= mv²/R + mg

taking m common

N= m( v²/R +g)

   = 71.4( (200)²/ 800 + 9.8 )

 Force  = 4270 N