Answer:
These four subsystems are called "spheres." Specifically, they are the "lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air). Each of these four spheres can be further divided into sub-spheres.
Explanation:
These four subsystems are called "spheres." Specifically, they are the "lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air). Each of these four spheres can be further divided into sub-spheres.
Answer:
B
Explanation:
They lose energy and slow down and move closer to other gas molecules and the molecules collect together to form a liquid
Answer:
Moles of Carbon in the product = 0.183 mol
Explanation:
Complete combustion of an organic compound in the presence of excess oxygen will give carbon dioxide (CO2) and water vapour(H2O).
Equation of reaction
CxHyOz(s) + (2x + y/2 - z)/2 O2(g) --> x CO2(g) + y/2 H2O(l)
Moles of products
CO2
Molar mass of CO2 = 12 + (16*2)
= 44 g/mol
n(CO2) = 8.07/44.0
= 0.183 mol
One compound of CO2 has 1 Carbon atom and 2 Oxygen atom.
So if we have,
0.183 moles of carbon dioxide then
0.183 moles of carbon.
The mass of carbon in the product, m = 0.183*12
= 2.20 g
H2O:
Molar mass of H2O = (1*2) + 16
= 18 g/mol
Number of moles of H2O =
= 3.3/18
= 0.183 mol
One compound of H2O has 2 Hydrogen atom and 1 Oxygen atom.
0.183 moles of water then we also have
= 2*(0.183)
= 0.367 moles of hydrogen in the sample.
The mass of hydrogen in the compound, m
= 0.367*1
= 0.367 g
Adding these two values together will give us the mass of our compound that C and H;
2.2 + 0.367
= 2.567 g
So for the Oxygen,
5.5 g - 2.567
= 2.933 g
Moles of Oxygen;
Molar mass of O = 16 g/mol
= 2.933/16
= 0.183 mol
Ethanol
The compound is in the Alcohol series.
