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aniked [119]
3 years ago
8

Complete and balance each equation. If no reaction occurs write N/R. NaOH(aq) + FeBr3(aq)

Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0
FeBr3(aq) + NaOH(aq) = FeOH(s) + NaBr3(aq) 
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When two aqueous solutions are combined the reaction forms a solid that settles out of solution. What is this solid called?
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During the chemical reaction, the solid substance that is insoluble formed during the combination of two aqueous solutions is called a precipitate. The answer is letter C. The precipitation reaction occurs when a salt is formed in the reaction of solutions with salts. 
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The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

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8 0
3 years ago
6. What is the number of moles of KF in a 29 gram sample?
stich3 [128]
Not sure but it might be A or B
3 0
3 years ago
True or False: The solute is ALWAYS a solid and the solvent is ALWAYS a liquid
sasho [114]

Answer:

false

Explanation:

Note that the solvent is the substance that is present in the greatest amount. Many different kinds of solutions exist. For example, a solute can be a gas, a liquid or a solid. ... Note that in each case, the solute particles are uniformly distributed among the solvent particles.

7 0
3 years ago
Read 2 more answers
One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.00 liters against a constant external pressure
Leya [2.2K]

Answer : The work done on the surroundings is, 709.1 Joules.

Explanation :

The formula used for isothermally irreversible expansion is :

w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)

where,

w = work done

p_{ext} = external pressure = 1.00 atm

V_1 = initial volume of gas = 1.00 L

V_2 = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

w=-p_{ext}(V_2-V_1)

w=-(1.00atm)\times (8.00-1.00)L

w=-7L.atm=-7\times 101.3J=-709.1J

The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.

Therefore, the work done on the surroundings is, 709.1 Joules.

4 0
3 years ago
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