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2 years ago

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A hollow metal sphere is electrically neutral (no excess charge). A small amount of negative charge is suddenly placed at one po

int P on this metal sphere. If we check on this excess negative charge a few seconds later, we will find one of the following possibilities:

1 answer:

Marizza181 [45]2 years ago

4 0

Answer:

The excess charge has distributed itself evenly over the outside surface of the sphere.

Explanation:

Since the hollow sphere is a conductor, it has free electrons that can move about within the sphere. In this light, an excess charge, the like charges repels each other, therefore ensuring that charges are spread as far apart as possible. There is therefore an evenly distributed charge on the outside surface of the sphere.

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Explanation:

The Doppler shift equation is:

$f'=\frac{V+V_{o}}{V-V_{s}} f$

Where:

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$f'=8.002(10)^{4} Hz$ is the "observed" frequency

$V=1570 m/s$ is the speed of sound

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2 years ago

The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various

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Answer:

$q = -461532.5 \ C$

Explanation:

From the question we are told that

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Generally according to Gauss law

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Given that the electric field is pointing downward , the equation become

$- E A = \frac{q}{\epsilon_o }$

Here $q$ is the excess charge on the surface of the earth

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Where r is the radius of the earth which has a value $r = 6.3781*10^6 m$

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$\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

substituting values

$q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}$

$q = -461532.5 \ C$

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3 years ago

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