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Allushta [10]
3 years ago
10

A hollow metal sphere is electrically neutral (no excess charge). A small amount of negative charge is suddenly placed at one po

int P on this metal sphere. If we check on this excess negative charge a few seconds later, we will find one of the following possibilities:
Physics
1 answer:
Marizza181 [45]3 years ago
4 0

Answer:

The excess charge has distributed itself evenly over the outside surface of the sphere.

Explanation:

Since the hollow sphere is a conductor, it has free electrons that can move about within the sphere. In this light, an excess charge, the like charges repels each other, therefore ensuring that charges are spread as far apart as possible. There is therefore an evenly distributed charge on the outside surface of the sphere.

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The emf induced in the second coil is given by:

V = -M(di/dt)

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The current in the first coil is given by:

i = i₀e^{-at}

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i = 5.0e^(-2.0×10³t)

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Plug in and solve for V:

V = -32×10⁻³(-1.0×10⁴e^(-2.0×10³t))

V = 320e^(-2.0×10³t)

We want to find the induced emf right after the current starts to decay. Plug in t = 0s:

V = 320e^(-2.0×10³(0))

V = 320e^0

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t - Final time, measured in seconds.

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