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Stolb23 [73]
3 years ago
10

You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

sion. The middle (D) string on the guitar should have fundamental frequency 146.83 Hz. The highest (E) string should have fundamental frequency 329.63 Hz. If the D string has linear mass density 0.00256kg/m, what should be the mass density of the E string
Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

\mu = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

So

f\propto \sqrt{\dfrac{1}{\mu}}

\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m

The mass density of the E string is 0.000507 kg/m

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Ahat [919]
Hi,Find  answers from Task 5

1.(X+4)+(X)+(X+4)+(X)=50cm

4x+8=50cm

4x=42

X=10.5cm

Length=10.5+4=14.5cm

Width=10.5cm

Area= length × width=(10.5/100) × (14.5/100) =0.0152m2

2. Volume of a sphere= 4/3 ×π×r³

4/3 ×π×r³=3.2×10^-6 m³

r³=3.2×10^-6 m³/1.33×π

r³=7.64134761e-7

r=0.00914m

Surface area of the blood drop= 4πr²

=4×3.142×0.00914×0.00914=0.00105m²

3.

Equation of an ideal gas     = PV =n RT  

Equation for pressure, = P= n RT/V

Equation for the volume of an ideal gas= V= n RT/P

If the volume of gas doubles ,V(new)=  2n RT/P

Equation for temperature of an ideal gas, T = PV/n R

If temperature of gas triples, T (new)= 3PV/n R

New Equation for Pressure, = n× R× (3PV/n R)/(2n RT/P)

Pressure factor increase= P(new)/P(old)  ={ n× R× (3PV/n R)/(2n RT/P)}/{ n RT/V}

=3PV²/2n RT
5 0
3 years ago
What is the period of a wave if the wavelenght is 110m and the speed is 200m/s? 2 s 100s 200,000 s 0.5 s
cestrela7 [59]
Hello.

The answer would be <span> 0.5 s

Have a nice day</span>
8 0
3 years ago
Read 2 more answers
Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the
svetoff [14.1K]

Answer:

\mu_k=0.18

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

x: T+F-f_k=0\\\\y:N-mg=0

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since f_k=\mu_k N and N=mg, we can rewrite the first equation as:

T+F-\mu_k mg=0

Now, we solve for \mu_k and calculate it:

\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

6 0
3 years ago
13. For an object to appear transparent, what interaction must occur between light waves and the object they hit?
Svetlanka [38]

Answer:

The answer is B

Explanation:

The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.

6 0
2 years ago
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Natalija [7]

Answer:

I think its (A)The specific heat of an object explains  how easily it changes temperatures.

Explanation:

6 0
3 years ago
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