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4 years ago

Is Explosion of nitroglycerin a chemical or physical change

Chemistry

2 answers:

Fynjy0 [20]4 years ago

8 0

It's a chemical change beacause elements are combining to make something new! :)

USPshnik [31]4 years ago

5 0

Ok......
Nitroglycerin is a Compound. If you explode nitroglycerin would produce C02 and H20. That would be a looottt of energy so it would be a chemical change.

H0P3 It H3LPS :)

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A common form of abuse of amphetamines that can damage the body is

jok3333 [9.3K]

Child abuse would be the best answer as child abuse is a common form of abuse

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3 years ago

Mercury has a density of 13.56 g/ml. What is the volume in L of 52 kg of mercury?

sweet [91]

Hello!

Given the density of mercury being 13.57 g/mL, and the mass of 52 kilograms, we need to find the volume.

To find the volume, we need to divide mass by density (V = m/d).

Notice that you are given 52 kilograms, but not grams. To convert kilograms to grams, you need to multiply it by 1000.

52 x 1000 = 52000 grams

With the correct measurements, we can find the volume.

V = 52000 grams / 13.56 grams/milliliter

V ≈ 3834.80826

Therefore, the volume of the mercury is about 3,834.81 mL.

5 0

4 years ago

How many grams of c6h12o6 are in 1. 90 x 1022 molecules of c6h12o6? the molar mass of c6h12o6 is 180. 0 g/mol. avogadro's number

d1i1m1o1n [39]

5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.

The mass per unit amount of a certain chemical entity is known as the molar mass (symbol M, SI unit kgmol1). The chemical entity in question should always be identified in accordance with the mole definition.

The number of atoms present in 1 mole of hydrogen is equal to 6.02 × 10²³ known as Avogadro’s number (NA).

The units of molar mass follow its definition; grams per mole. Mathematically, the defining equation of molar mass is

Molar mass = mass/mole = g/mol

180g/mol glucose has = 6.02 × 10²³

x g/mol glucose has = 1.90 × 10 ²²

To find x;

$x = \frac{180.0 * 1.90 * 10^2^2}{6.02 * 10^2^3}$

x = 5.6 × 10⁻³ g/mol

Therefore, 5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.

Learn more about molar mass here:

brainly.com/question/837939

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2 years ago

How does aspirin interact with other drugs

Damm [24]

The most common drugs that aspirin may interact with are: Anti-inflammatory painkillers, such as diclofenac, ibuprofen, indomethacin, and naproxen. Taken with aspirin, these can increase the risk of bleeding. Warfarin, an anticoagulant drug, or a blood thinner, which stops the blood from clotting.

7 0

4 years ago

1.00 M CaCl2 Density = 1.07 g/mL

Lesechka [4]

Explanation:

Molarity of solution = 1.00 M = 1.00 mol/L

In 1 L of solution 1.00 moles of calcium chloride is present.

Mass of solute or calcium chloride = m

$m = 1 mol\times 111 g/mol = 111 g$

Mass of solution = M

Volume of solution = V = 1L = 1000 mL

Density of solution , d= 1.07 g/mL

$M=d\times V=1.07 g/mL\times 1000 mL=1,070 g$

1) The value of %(m/M):

$\frac{m}{M}\times 100=\frac{111 g}{1,070 g}\times 100=10.37\%$

2) The value of %(m/V):

$\frac{m}{V}\times 100=\frac{111 g}{1000 L}\times 100=11.1\%$

$Molality = \frac{\text{Moles of compound }}{\text{mass of solvent in kg}}$

$Normality=\frac{\text{Moles of compound }}{n\times \text{volume of solution in L}}$

n = Equivalent mass

n = $\frac{\text{molar mass of ion}}{\text{charge on an ion}}$

3) Normality of calcium ions:

Moles of calcium ion = 1 mol (1 $CaCl_2$ mole has 1 mole of calcium ion)

$n=\frac{40 g/mol}{2}=20$

$=\frac{1 mol}{20 g/mol\times 1L}=0.050 N$

4) Normality of chlorine ions:

Moles of chlorine ion = 2 mol (1 $CaCl_2$ mole has 2 mole of chlorine ion)

$n=\frac{35.5 g/mol}{1}=35.5$

$=\frac{2 mol}{35.5 g/mol\times 1L}=0.056 N$

Moles of calcium chloride = 1.00 mol

Mass of solvent = Mass of solution - mass of solute

= 1,070 g - 111 g = 959 g = 0.959 kg ( 1 g =0.001 kg)

5) Molality of the solution :

$\frac{1 mol}{0.959 kg}=1.043 mol/kg$

Moles of calcium chloride = $n_1=1mol$

Mass of solvent = 959 g

Moles of water = $n_2=\frac{959 g}{18 g/mol}=53.28 mol$

Mass of solvent = 959 g

6) Mole fraction of calcium chloride =

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{1mol}{1 mol+53.28 mol}=0.01842$

7) Mole fraction of water =

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{53.28 mol}{1mol+53.28 mol}=0.9816$

8) Mass of solution = m'

Volume of the solution= v = 100 mL

Density of solution = d = 1.07 g/mL

$m'=d\times v=1.07 g/ml\times 100 g= 107 g$

Mass of 100 mL of this solution 107 grams of solution.

9) Volume of solution = V = 100 mL

Mass of solution = M'' = 107 g

Mass of solute = m

The value of %(m/V) of solution = 11.1%

$11.1\%=\frac{m}{100 mL}\times 100$

m = 11.1 g

Mass of solvent = M''- m = 107 g -11.1 g = 95.9 g

95.9 grams of water was present in 100 mL of given solution.

3 0

3 years ago