Question

e 2.2 kg block. Answer in units of m/sA 5 kg block moving at 2.3 m/s makes a head-on elastic collision with a stationary block of mass 2.2 kg. Find the velocity of the 2.2 kg block. Answer in units of m/s

Answer 1

Answer: The velocity of the 2.2 kg block is 5.23 m/s

Explanation:

To calculate the velocity of the 2.2 kg block after the collision, we use the equation of law of conservation of momentum, which is:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,  

$m_1$ = mass of block 1 = 5 kg

$u_1$ = Initial velocity of block 1 = 2.3 m/s

$v_1$ = Final velocity of block 1 = 0 m/s

$m_2$ = mass of block 2 = 2.2 kg

$u_2$ = Initial velocity of block 2 = 0 m/s

$v_2$ = Final velocity of block 2 = ?

Putting values in above equation, we get:

$(5\times 2.3)+(2.2\times 0)=(5.0\times 0)+(2.2\times v_2)\\\\v_2=\frac{(5\times 2.3)}{2.2}=5.23m/s$

Hence, the velocity of the 2.2 kg block is 5.23 m/s