Answer:
(absolute).
Explanation:
Given that
Pressure ratio r
r=8

-----1
P₁(gauge) = 5.5 psig
We know that
Absolute pressure = Atmospheric pressure + Gauge pressure
Given that
Atmospheric pressure = 14.5 lbf/in²
P₁(abs) = 14.5 + 5.5 psia
P₁(abs) =20 psia
Now by putting the values in the above equation 1
Therefore the exit gas pressure will be 160 psia (absolute).
So they can grasp a better understanding! good luck
Answer:
Check the explanation
Explanation:
class LanguageHelper:
language=set()
#Constructor
def __init__(self, words):
for w in words:
self.language.add(w)
def __contains__(self,query):
return query in self.language
def getSuggestionns(self,query):
matches = []
for string in self.language:
if string.lower().startswith(query) or query.lower().startswith(string) or query.lower() in string.lower():
matches.append(string)
return matches
lh = LanguageHelper(["how","Hi","What","Hisa"])
print('how' in lh)
print(lh.getSuggestionns('hi'))
===========================================
OUTPUT:-
==================
True
['Hisa', 'Hi']
====
Answer:0.3166N
Explanation:
Given data
Area 
Gap below top plate
Gap above bottom plate
SAE 30 oil viscosity =
Velocity of middle plate
There will viscous force on middle plate i.e. at above surface and below surface
Viscous force
![Net Force on plate F =\mu Av\left [\frac{1}{y_1} +\frac{1}{y_2}\right ]](https://tex.z-dn.net/?f=Net%20Force%20on%20plate%20F%20%3D%5Cmu%20Av%5Cleft%20%5B%5Cfrac%7B1%7D%7By_1%7D%20%2B%5Cfrac%7B1%7D%7By_2%7D%5Cright%20%5D)
![F=0.38\times 500\times 10^{-4}\left [\frac{1}{20\times 10^{-3}} +\frac{1}{30\times 10^{-3}}\right ]](https://tex.z-dn.net/?f=F%3D0.38%5Ctimes%20500%5Ctimes%2010%5E%7B-4%7D%5Cleft%20%5B%5Cfrac%7B1%7D%7B20%5Ctimes%2010%5E%7B-3%7D%7D%20%2B%5Cfrac%7B1%7D%7B30%5Ctimes%2010%5E%7B-3%7D%7D%5Cright%20%5D)

this is force by oil on plate thus we need to apply atleast 0.3166N to move plate