Answer:
Yes, fracture will occur
Explanation:
Half length of internal crack will be 4mm/2=2mm=0.002m
To find the dimensionless parameter, we use critical stress crack propagation equation
and making Y the subject
Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness, 
is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain
When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m
and making K the subject
and substituting 260 MPa for 
while a is taken as 0.003m and Y is already known
Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material
(a) The solution to the system of equation is, x = (d + b)/(ad - cb) and y = (-a - c)/(ad - cb).
(b) The condition at which the solution exists is, ad - cb ≠ 0.
<h3>
Solving the system of equation with Cramer's rule</h3>
ax + by = 1
cx + dy = -1
D = [a b]
[c d]
D = ad - cb
Dx = [1 b]
[-1 d]
Dx = d + b
Dy = [a 1]
[c - 1]
Dy = -a - c
x = Dx/D
x = (d + b)/(ad - cb)
y = Dy/D
y = (-a - c)/(ad - cb)
Cramer's rule applies to the case where the coefficient determinant is nonzero.
Thus, D ≠ 0 (ad - cb ≠ 0).
Learn more about Cramer's rule here: brainly.com/question/10445102
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Answer:
The three phase full load secondary amperage is 2775.7 A
Explanation:
Following data is given,
S = Apparent Power = 1000 kVA
No. of phases = 3
Secondary Voltage: 208 V/120 V <em>(Here 208 V is three phase voltage and 120 V is single phase voltage) </em>
<em>Since,</em>
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The formula for apparent power in three phase system is given as:
Where:
S = Apparent Power
V = Line Voltage
I = Line Current
In order to calculate the Current on Secondary Side, substituting values in above formula,
Answer:
i have no clue brother i just came here for points
Explanation:
