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qwelly [4]
3 years ago
14

This is a blueprint drawing of the stage area at Millennium Park. The length of one square on the grid is equal to 5 feet. Accor

ding to the blueprint, the length of the diagonal of square C is 60 feet. Is that correct? Explain. (2 points).
Engineering
1 answer:
Goshia [24]3 years ago
3 1

Answer:

This is a blueprint drawing of the stage area at Millennium Park. The length of one square on the grid is equal to 5 feet. According to the blueprint, the length of the diagonal of square C is 60 feet. Is that correct? Explain. (2 points).

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3 years ago
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In C++ the declaration of floating point variables starts with the type name float or double, followed by the name of the variab
zubka84 [21]

Answer:

The given grammar is :

S = T V ;

V = C X

X = , V | ε

T = float | double

C = z | w

1.

Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.

From the given grammar,

Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.

No other variables generate variable X or ε.

So, only variable X is nullable.

2.

First of nullable variable X is First (X ) = , and ε (epsilon).

L.H.S.

The first of other varibles are :

First (S) = {float, double }

First (T) = {float, double }

First (V) = {z, w}

First (C) = {z, w}

R.H.S.

First (T V ; ) = {float, double }

First ( C X ) = {z, w}

First (, V) = ,

First ( ε ) = ε

First (float) = float

First (double) = double

First (z) = z

First (w) = w

3.

Follow of nullable variable X is Follow (V).

Follow (S) = $

Follow (T) = {z, w}

Follow (V) = ;

Follow (X) = Follow (V) = ;

Follow (C) = , and ;

Explanation:

4 0
3 years ago
Calculate the maximum load that a 7075 series aluminum alloy bar (with a T6 temper heat treatment) can support without permanent
Aleksandr [31]

Answer:

The maximum load the bar can withstand = 35.43 KN

Explanation:

Ultimate tensile strength of the given aluminium bar \sigma = 540 M pa

Cross section area of the bar = 8.1^{2}  = 65.61 mm^{2}

We know that the ultimate strength of the bar is calculated from

\sigma = \frac{P_{max} }{A}

540 = \frac{P_{max} }{65.61}

P_{max} = 540 × 65.61

P_{max} =  35.43 KN

Therefore the maximum load the bar can withstand = 35.43 KN

6 0
3 years ago
Calculate the biaxial stresses σ1 and σ2 for the biaxial stress case, where ε1 = .0020 and ε2 = –.0010 are determined experiment
Llana [10]

Answer:

i) σ1 = 133.5 MPa

  σ2 = -2427 MPa

ii) 78.89 MPa

Explanation:

Given data:

ε1 = 0.0020 and ε2 = –0.0010

E = 71 GPa

v = 0.35

<u>i) Determine the biaxial stresses  σ1 and σ2 using the relations below</u>

ε1 = σ1 / E - v (σ2 / E)   -----( 1 )

ε2 = σ2 / E - v (σ1 / E)  -------( 2 )

resolving equations 1 and 2

σ1 = E / 1 - v^2 {  ε1 + vε2 } ---- ( 3 )

σ2 = E / 1 - v^2 {  ε2 + vε1 } ----- ( 4 )

input the given data into equation 3 and equation 4

σ1 = 133.5 MPa

σ2 = -2427 MPa

<u>ii) Calculate the value of the maximum shear stress ( Zmax )</u>

Zmax = ( σ1 - σ2 ) / 2

         = 133.5 - ( - 2427 ) / 2

         = 78.89 MPa

3 0
3 years ago
Design the software architecture for a student online registration system using the MVC architecture. Draw the architecture by s
Travka [436]

MVC architecture is defined as the architectural design that is used by software engineers for programming languages.

<h3>What are the various models of MVC architecture?</h3>

The various types of MVC architecture include the following:

  • The controller: This model is used to control logic and acts as the coordinator between the View and the Model.

  • The view: It displays the information from the model to the user.

  • The model: It is used to implement the domain logic.

Learn more about software here:

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#SPJ1

8 0
2 years ago
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