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2 years ago

What's needed to know

2 answers:

8 0

You're a little late. But if you want some short, quick rules, then these are
a couple that I would take in with me (stored only in my brain, of course):

-- If something is not accelerating or moving at all, then all the forces on it
must add up to zero. That could even mean a hanging rope.

-- In a vertical rope, the tension in it is the same everywhere in the rope.
The tension is the weight of whatever is hanging from the bottom.

That's really all I'm sure of, based on your hazy, fuzzy description of
what you've been doing in class. I don't want to get into things that
you might not have learned yet, and confuse you.

Orlov [11]2 years ago

5 0

You're absolute best bet is to read and re-read the entire chapter one of the book. This is for an absolute best strategy. On the other hand, there are usually key words and terms that are highlighted that most teachers use as a frame for test taking. Studying those highlighted words would be the next best bet. If there are no highlighted words, tough luck. You need to figure out what is important. Which is part of the learning process, and also why I won't directly answer your question. I care more about you learning than you getting a good grade.

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A psychologist claiming that a client's personal experiences and viewpoint influence behavior more than events in reality is usi

vodka [1.7K]

A psychologist who would claim that a client's personal experience and viewpoint influence behavior more than events in reality would probably use cognitive psychology mixed with developmental aspects to explain the behavior and personality of a person.

5 0

2 years ago

Read 2 more answers

A wheel rotates with a constant angular acceleration of  rad/s2. During a certain time interval its angular displacement is  r

Hatshy [7]

Answer:

The angular velocity at the beginning of the interval is $\pi\sqrt{2}\ rad/s$ .

Explanation:

Given that,

Angular acceleration $\alpha=\pi\ rad/s^2$

Angular displacement $\theta=\pi\ rad$

Angular velocity $\omega =2\pi\ rad/s$

We need to calculate the angular velocity at the beginning

Using formula of angular velocity

$\alpha =\dfrac{\omega^2-\omega_{0}^2}{2\theta}$

$\omega_{0}^2=\omega^2-2\alpha\theta$

Where, $\alpha$ = angular acceleration

$\omega$ = angular velocity

Put the value into the formula

$\omega_{0}^2=(2\pi)^2-2\times\pi\times\pi$

$\omega=\sqrt{2\pi^2}$

$\omega_{0}=\pi\sqrt{2}\ rad/s$

Hence, The angular velocity at the beginning of the interval is $\pi\sqrt{2}\ rad/s$ .

3 0

3 years ago

When is a secondary source more helpful than a primary source?

UNO [17]

Answer:

I think the answer is C.

Explanation:

A primary source is a first hand account of an event while a secondary source is a retelling or second hand account meaning as many details will be prevalent.

8 0

2 years ago

What is the total resistance in this circuit?

VikaD [51]

Try 40. it seems correct. i’m sorry if i’m wrong.

6 0

2 years ago

Basalt, formed from magma, contains iron-rich minerals. Why is this important?

Svetach [21]

Iron is a magnetic metal, and it is essential to the Earth's magnetic field!
Essentially it "records" (stores the information, maintains) the direction and orientation of the magnetic field.

Among others, the magnetic field protects the Earth from dangerous cosmic rays.

5 0

2 years ago