Ask question

Ask question

All categories

3 years ago

6

A worker wants to load some bricks in to his van. there are 1000 bricks and when stacked neatly they measure 2m by 1m by 1m, wha

t is the volume of the stack

1 answer:

inessss [21]3 years ago

8 0

lenddbisnwjw whwjwiwnww

You might be interested in

Identify a situation in which you would want to have a high

Andreyy89

Answer: A voltmeter must have a high resistance where as an ammeter must have a low resistance.

Explanation:

A voltmeter is a device which is connected in parallel to the component across which voltage needs to be measured. In a parallel circuit voltage drop is same at the nodes. The parallel connection must not offer easier path for current to divert from the main circuit and travel. Thus, a voltmeter must have high resistance.

On the other hand, an ammeter which is used to measure current in the circuit must have low resistance as it is connected in series. It should not offer resistance as it would reduce the actual current and measurement would be inaccurate.

7 0

4 years ago

Read 2 more answers

The velocity of an object is the _____ of the object

katovenus [111]

D. Speed and direction, this is because velocity is a vector quantity so has a magnitude and direction assigned to it because it is the rate of change of displacement.

6 0

3 years ago

What does more damage; a slow semi truck, or a fast sports car

Goshia [24]

The fast sports car does more damage then the slow semi truck

7 0

3 years ago

Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ

Oksi-84 [34.3K]

Answer:

The number is $Z = 216 \ fringes$

Explanation:

From the question we are told that

The wavelength is $\lambda = 520 \ nm = 520 *10^{-9} \ m$

The length of the glass plates is $y = 21.1cm = 0.211 \ m$

The distance between the plates (radius of wire ) = $d = 0.028 mm = 2.8 *10^{-5} \ m$

Generally the condition for constructive interference in a film is mathematically represented as

$2 * t = [m + \frac{1}{2} ]\lambda$

Where t is the thickness of the separation between the glass i.e

t = 0 at the edge where the glasses are touching each other and

t = 2d at the edge where the glasses are separated by the wire

m is the order of the fringe it starts from 0, 1 , 2 ...

So

$2 * 2 * d = [m + \frac{1}{2} ] 520 *10^{-9}$

=> $2 * 2 * (2.8 *10^{-5}) = [m + \frac{1}{2} ] 520 *10^{-9}$

=>

$m = 215$

given that we start counting m from zero

it means that the number of bright fringes that would appear is

$Z = m + 1$

=> $Z = 215 +1$

=> $Z = 216 \ fringes$

3 0

3 years ago

A tennis player tosses a tennis ball straight up and then catches it after 1.25 s at the same height as the point of release.

Alenkasestr [34]

Answer:

A. 9.8 m/s²

B. Zero

C. 6.125 m/s

D. 1.91 m

Explanation:

From the question given above, the following data were obtained:

Time (T) spent in the air = 1.25 s

A. Determination of the acceleration of the ball.

From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²

B. Determination of the velocity at maximum height.

Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.

C. Determination of the initial velocity of the ball.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Time (T) spent in the air = 1.25 s

Time (t) to reach the maximum height =?

T = 2t

1.25 = 2t

Divide both side by 2

t = 1.25 / 2

t = 0.625 s

Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:

Time (t) to reach the maximum height = 0.625 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 0.625)

0 = u – 6.125

Collect like terms

0 + 6.125 = u

u = 6.125 m/s

Thus, the initial velocity of the ball is 6.125 m/s

D. Determination of the maximum height.

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) = 6.125 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 6.125² – (2 × 9.8 × h)

0 = 37.52 – 19.6h

Collect like terms

0 – 37.52 = – 19.6h

– 37.52 = – 19.6h

Divide both side by – 19.6

h = – 37.52 / – 19.6

h = 1.91 m

Thus, the maximum height reached by the ball is 1.91 m

3 0

3 years ago