Answer:
<h3> 1.40625m/s²</h3>
Explanation:
Using the equation of motion expressed as v = u+gt where;
v is the final velocity of the ball
u is the initial velocity
g is the acceleration due to gravity
t is the time taken
Given
u = 9m/s
v = 0m/s
t = 6.4s
Required
acceleration due to gravity g
Since the rock is thrown up, g will be a negative value.
v = u+(-g)t
0 = 9-6.4g
-9 = -6.4g
6.4g = 9
divide both sides by 6.4
6.4g/6.4 = 9/6.4
g = 1.40625m/s²
Hence the acceleration due to gravity on the planet is 1.40625m/s²
Answer:
230 N
Explanation:
At the lowest position , the velocity is maximum hence at this point, maximum support force T is given by the branch.
The swinging motion of the ape on a vertical circular path , will require
a centripetal force in upward direction . This is related to weight as follows
T - mg = m v² / R
R is radius of circular path . m is mass of the ape and velocity is 3.2 m/s
T = mg - mv² / R
T = 8.5 X 9.8 + 8.5 X 3.2² / .60 { R is length of hand of ape. }
T = 83.3 + 145.06
= 228.36
= 230 N ( approximately )
