Answer:
Second option 6.3 N at 162° counterclockwise from
F1->
Explanation:
Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.
For the address x we have:

For the address and we have:

The forces
and
are known

We have 2 unknowns (
and b) and we have 2 equations.
Now we clear
from the second equation and introduce it into the first equation.

Then

Then we find the value of 

Finally the answer is 6.3 N at 162° counterclockwise from
F1->
Answer:
Six meters refers to the distance the baseball travels in one second.
Explanation:
6 m/s means that every second, the baseball travels 6m. So, 6 meters is the distance traveled in one second.
Answer:
College student's commitment
Explanation:
The dependent variable is the college students since it is the variable we are going to measure as a result of the independent variable which is the hazardous hazing ritual or non-hazardous hazing ritual.