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3 years ago

10

How much charge flows from a 6.0 v battery when it is connected across a completely discharged 15.7 μf capacitor?

1 answer:

Lilit [14]3 years ago

4 0

The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 6.0V (assuming circuit resistance is negligable) and it has a capacitance of 15.7<span>μf or </span> 15.7x10^-6f, therefore charge equals (15.7x10^-6)x6=9.42x10^-5C (Coulombs).

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A hot air ballo0n is ascending straight up at a constant

finlep [7]

Answer: The two places altitudes are: 16.17 m and 40.67 m

Explanation:

Hi!

Lets call z to the vertical direction (z= is ground) . Then the positions of the balloon and the pellet, using the values of the velocities we are given, are:

$z_b =\text{balloon position}\\z_p=\text{pellet position}\\z_b=(7\frac{m}{s})t\\z_p=30\frac{m}{s}(t-t_0)-\frac{g}{2}(t-t_0)^2\\g=9.8\frac{m}{s^2}$

How do we know the value of t₀? This is the time when the pellet is fired. At this time the pellet position is zero: its initial position. To calculate it we know that the pellet is fired when the ballon is in z = 12m. Then:

$t_0=\frac{12}{7}s$

We need to know the when the z values of balloon and pellet is the same:

$z_b=z_p\\(7\frac{m}{s})t =30\frac{m}{s}(t-\frac{12}{7}s)-\frac{g}{2}(t-\frac{12}{7}s)^2$

We need to find the roots of the quadratic equation. They are:

$t_1=2.31s\\t_2=5.81$

To know the altitude where the to objects meet, we replace the time values:

$z_1=16,17m\\z_2=40,67m$

7 0

3 years ago

1. The potential difference between the terminals a cell in open circuit is 2.2volt. With resistance of 5ohm across the terminal

nadya68 [22]

Explanation:

10 /9 Ω

potential difference across the cell in open circuit is the emf of the cell.

Hence, emf E=2.2V

when, circuit is closed, potential difference across cell is given by V=E−Ir

And,

I= E/ R+r

Hence, V= E− Er/ R+r

⟹ V= ER/ R+r

⟹ 1.8= 2.2×5 /5+r

⟹9+1.8r=11

⟹ r= 2/ 1.8 Ω

⟹ r= 10/9 Ω

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2 years ago

What is the mass m of the elevator? use g=10m/s2 for the magnitude of the acceleration of gravity.

emmasim [6.3K]

Need more info..............

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2 years ago

What is the displacement of the GBS cross-country team if they begin at the school, run 10 miles, and finish back at the school?

olga2289 [7]

Answer:

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Explanation:

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2 years ago

A ship travels with velocity given by 12, with current flowing in the direction given by 11 with respect to some co-ordinate axe

nataly862011 [7]

Answer:

$v_x = 11.78 m/s$

Explanation:

Velocity of the ship is given as

$v = 12 units$

the direction of the velocity of the ship is making an angle of 11 degree with the current

so we will have two components of the velocity

1) along the direction of the current

2) perpendicular to the direction of the current

so here we know that the component of the ship velocity along the direction of the current is given as

$v_x = v cos\theta$

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2 years ago