Answer:
The winding density of the solenoid, n = 104 turns/m
Explanation:
Given that,
Length of the solenoid, l = 0.7 m
Radius of the circular cross section, r = 5 cm = 0.05 m
Energy stored in the solenoid,
Current, I = 0.4 A
To find,
The winding density of the solenoid.
Solution,
The expression for the energy stored in the solenoid is given by :
Where
L is the self inductance of the solenoid
n is the winding density of the solenoid
n = 104 turns/m
So, the winding density of the solenoid is 104 turns/m
The nearest star that can go supernova is either Spica or IK Pegasi
The agriculture land needed to grow the willow is 1500000 Hectares
<h3>What is Power?</h3>
Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
A coal burning power station burns 6 million tonnes of coal per kg. Coal has a average energy value of 29.25 MJ per year. Wood chip from willow trees has an energy value of 13 MJ per kg. A hectare of agricultural land can produce 9 tonnes of drt willow wood per year.
The coal consumption per year = 29.25 x 1000 x 6000000
=175500000000 MJ
If this power station burned dry willow wood instead of coal, agriculture land would be needed to grow the willow,
1 hectare of willow will produce 9 x 13x 1000 = 117000 MJ.
The agriculture land needed to grow the willow is
= 175500000000 MJ / 117000 MJ.
= 1500000 Hectares.
Thus, agriculture land needed is 1500000 Hectares.
Learn more about power.
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Yes, Weightlifters are truly working out.
Explanation:
- Definition of work in physics is the transfer of energy when an object is being moved. But, when an object is being lifted then net work done is zero because of the gravitational force acting on it.
- But, if we speak in terms of transferring energy then there is a workout. For example, if you push a bench and it moves. there is a transfer of energy to the bench and it moves.
- Here, when you lift a weight, it burns your calories and also there is a movement for the weight also.
<u>Given </u>
velocityΔ v₁ = 6m/s
v₂ = 11m/s
Δ time = Δ t = 2s
<u><em>sign / indicate as division.</em></u>
acceleration a = Δv/ Δt
a = (v₂-v₁) / Δt
a = (11m/s -6m/s ) / 2s
a = (5m/s) / 2s
<u>accerelation </u> a = 2.5m