Question

A 2300 kg truck has put its front bumper against the rear bumper of a 2500 kg suv to give it a push. with the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 n. you may want to review ( pages 145 - 146) . part a what is the maximum possible acceleration the truck can give the suv? express your answer to two significant figures and include the appropriate units.

Answer 1

From the Newton’s First Law, we can see that acceleration is simply the ratio of Force over mass. In this case, mass is the sum of the mass of each car, that is:

mass = 2300 kg + 2500 kg = 4800 kg

 

So the formula is:

acceleration = Force / mass

acceleration = 18,000 N / 4800 kg

acceleration = 3.75 m/s^2

 

In 2 significant figures:

acceleration = 3.8 m/s^2

Answer 2

The maximum possible acceleration the truck can give the SUV is about 3.8 m/s²

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Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\boxed {F = ma }$

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

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Given:

mass of truck = m = 2300 kg

mass of SUV = M = 2500 kg

maximum forward force = F = 18 000 N

Asked:

maximum possible acceleration = a = ?

Solution:

We will use Newton's second law of motion to solve this problem :

$\Sigma F = ( m + M )a$

$F = ( m + M ) a$

$a = F \div ( m + M )$

$a = 18000 \div ( 2300 + 2500 )$

$a = 18000 \div 4800$

$a \approx 3.8 \texttt{ m/s}^2$

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Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics