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4 years ago

A 1,000 kg car has 50,000 joules of kinetic energy. What is it’s speed

Physics

2 answers:

djverab [1.8K]4 years ago

6 0

Answer:

½mv²= KE

½(1000)?²= 50000

500*?²= 50000

/500 /500

? ²=100

Square root

?= 10

10 m/s is you answer

olganol [36]4 years ago

5 0

50,000/1,000

this is what you have to do you have to divide the killigrams by the juels

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Here is something to blow your mind. In one slice of "everything" pizza there are 650 Calories (1000 chemistry calories). That e

amid [387]

Answer:

Number of slices of pizza is 993.

Explanation:

It is given that, in one slice of "everything" pizza there are 650 Calories. The conversion factor from calories to joules is :

1 calorie = 4.184 joules

650 calories = 2719.6 joules

Total energy in the pizza, E = 2700000 J

Let there are n number of slices of pizza. It is given by :

$n=\dfrac{2700000}{2719.6}$

n = 992.79

n = 993

So, there are 993 slices of pizza. Hence, this is the required solution.

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Eli's gross income as a painter is $30,000 per year, which places him in the 15% approximate tax bracket. How much does he pay i

Umnica [9.8K]

Answer: $4,500

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3 years ago

A 75.0kg bicyclist (including the bicycle) is pedaling to the right, causing her speed to increase at a rate of 2.20m/s^2, despi

malfutka [58]

1) 4 forces

2) 165 N

3) 225 N

Explanation:

There are in total 4 forces acting on the bicylist:

- The gravitational force on the byciclist, acting vertically downward, of magnitude $mg$ , where m is the mass of the bicyclist and g is the acceleration due to gravity

- The normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational force

- The force of push F, acting horizontally forward, given by the push exerted by the bicylist on the pedals

- The air drag, R, of magnitude R = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist

The magnitude of the net force on the bicyclist can be calculated by considering separately the two directions.

- Along the vertical direction, we have the gravitational force (downward) and the normal force (upward); these two forces are equal in magnitude, since the acceleration of the bicyclist along this direction is zero, therefore the net force in this direction is zero.

- Along the horizontal direction, the two forces (forward force of push and air drag) are balanced, since the acceleration is non-zero, so we can use Newton's second law of motion to find the net force on the bicylist:

$F_{net}=ma$